Completing the square follows the principle of taking

and converting it into

where d is the 'correctional number' as I like to call it - i.e. the number that converts the expanded bracket into the +c, since the expanded bracket will give us

.
In this case, 2/2=1 so we have the first part:

.
Expanding this gives us

. We need c to be 9, so we can just add 8.
Putting this together:

Now we can solve it more easily.
Rearranging:

- Simplify ⇨ 19m + 14 - 3 (3m + 7)


Use the distributive property to multiply -3 by 3m+7.

Combine 19m and -9m to get 10m.

Subtract 21 from -14 to get -35.

Answer:
A = 5.5t + 9
Step-by-step explanation:
We assume that the relationship between t and A is linear.
We have two points on a line: (2, 20) and (4, 31).
We now find the equation of the line.
A = mt + b
m = (31 - 20)/(4 - 2) = 11/2 = 5.5
20 = 5.5(2) + b
20 = 11 + b
b = 9
A = 5.5t + 9
Answer:
x=4.5 and y= -6
Step-by-step explanation:
2x+5y= -21
-2x+3y= -27
add the two equations: 8y= -48
y=-48/8= -6
sub for y in 2x+5y= -21
2x + 5(-6)=-21, 2x-30= -21
2x= -21+30= 9
x= 9/2=4.5
Answer:
9 (m+5)-3(m-2)=8m+31
9m+45 - (3m + 6)= 8m+31
9m+45-3m-6=8m+31
45-6+31=8m-9m+3m
70=2m
m=70/2
Therefore m = 35
Hope u understood.............