Answer:
16 feet
Step-by-step explanation:
This ladder and building creates a right triangle with 34 as the hypotenuse and 30 as a side. the Pythagorean theorem says that a^2 + b^2 = c^2 so 900 + b^2 = 1156. b^2 = 256, square root both sides and you get b = 16
Answer:
John has 42 apples left
Step-by-step explanation:
77-20-15=42
Hope this helps
In fraction form, it’s 213333^4/ 10,000^4
Answer:
The numbers that represent this situation are 7 and 9.
Step-by-step explanation:
For this problem, we have to find two numbers that sum up to 16 and have a difference of 2.
First, let's list out the numbers the sum up to 16.
1 + 15
2 + 14
3 + 13
4 + 12
5 + 11
6 + 10
7 + 9
From this list, we can see that 7 and 9 are our numbers. 7 and 9 sum up to 16. When you subtract 7 from 9, then you will get a difference of 2.
<u>So, two numbers that have a sum of 16 and a difference of 2 are 7 and 9. </u>
1. Drawn a straight line AB =7 cm with the help of ruler.
2. With the help of compass drawn an arc from A and at the point where it cuts AB from that point made another arc drawn an arc cutting the previous arc.
3. From A drawn a straight line joining the arc and extend it to M.
4. With the help of ruler measured 5 cm and mark it as AC.
5. Joined BC and we get the required triangle.
6. From C drawn an arc and make it cut on AC and BC and from the point it cuts AC and BC drawn arc cutting each other and extend a line from point C extend a line to the point point of intersection of two arc.
7. Similarly we do for A and the point where the two line intersect denoted as O.
8. Made a perpendicular from O on AB this perpendicular will be radius and taking O as centre we draw a circle this is our incircle.
9. And AN is our locus of points equidistant from two lines AB and AC.
We need to construct a circle inscribed in triangle that is incircle it can be done by making angle bisector of two sides the point where it intersect will be incentre. The centre of required circle.
The angle bisector is the locus where points are equidistant from two sides.
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