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GarryVolchara [31]
3 years ago
7

Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X

. Arc X Z is 105 degrees and arc W Z is 175 degrees. In the diagram of circle A, what is the measure of ∠XYZ? 35° 70° 75° 140°
Mathematics
2 answers:
timama [110]3 years ago
5 0

Circle A is missing, so i have attached it.

Answer:

∠XYZ = 35°

Step-by-step explanation:

We want to find the angle ∠XYZ in the image attached.

To solve that, we will use the formula in the theorem for angle formed by secants or tangents. Thus;

∠XYZ = ½(arc WZ - arc XZ)

From the image, arc WZ = 175° and arc XZ = 105°

Thus;

∠XYZ = ½(175 - 105)

∠XYZ = ½(70)

∠XYZ = 35°

Naddika [18.5K]3 years ago
5 0

Answer:

Its A if you don't wanna read

Step-by-step explanation:

Edge

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Step-by-step explanation:

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Model with Math: What is the width of the rectangle written as an exponential expression?
jeka94

Answer:  The width is:  " 10 m " .

_____________

To express this answer as an "exponential expression" ; we can write this answer as:  " 10¹ m " .

_____________

Also, we can write the width as an unsimplified "exponential expression" as:

  " \frac{10^4}{10^3} m " .

_____________

Step-by-step explanation:

Area, "A" = L (length) * w (width ;

_____________

Since:  " A = L * w " ;

and since we are to find the width; "w" ;

let us rewrite the equation;

to isolate  "w" on one side of the equation:

_____________

 " A =  L * w " ;

Divide Each Side of the equation by "L" ;

  A / L = (L * w) / L ;

The " L's " on the "right-hand side" of the equation "cancel out" ;

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and we have:

  A / L = w ;

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_____________

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_____________

 w = A / L  ;

" w = A/L = \frac{10^4 m^2}{10^3 m} = 10^{(4-3)} m^{(2-1)} = 10^1m^1 = 10 m  ."

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_____________

Let us check our answer:

Area (A) = L (length) * w (width) ;

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_____________

→  10⁴ m²   ≟  10³ * 10¹ m * m ? ;

_____________

→  10⁴ m²   ≟  10⁽³⁺ ¹⁾ * m * m ? ;

→  10⁴ m²   ≟  10⁴ m² ?  Yes!

_____________

Other: Let us further check our answer; in a different format:

_____________

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Hope this is helpful.

Best of luck in your academic endeavors—& within "Brainly" !

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