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Andreyy89
3 years ago
9

How do I go about solving this?

Mathematics
1 answer:
Stels [109]3 years ago
4 0
Hello,

Here i am using vectors

\vec{AB}=\vec{DC}=3\vec{i}+3\vec{j}
==> AB//DC and AD//BC (definition of a translation)


The quadrilater ABCD is a parallelogram:
so
1) his diagonals have the same length;

2) his diagonals are cutting in the middle.

(these are proprieties of a parallelogram)
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What is 70/250 written as a percentage? A) 2.8% B) 28% C) 280% D) 2800%
cluponka [151]
B) 28 percent because it would be 2.8 if you had 7/250
5 0
3 years ago
2.
Strike441 [17]

Answer:

1/3

Step-by-step explanation:

Assuming that both die are labelled 1 - 6, the successful outcomes are 3 and 5 or 3 and 6. This is 2 out of the 6 possible outcomes so the answer is 2/6 or 1/3.

8 0
4 years ago
∠A and ​ ∠B ​ are vertical angles with m∠A=x and m∠B=5x−80 .<br><br> What is m∠A ?
nirvana33 [79]
20 degrees
vertical angles are equal, so 5x-80=x
solve for x and you get 20

4 0
4 years ago
What is the answer???
muminat

Answer:

21, 15

Step-by-step explanation:

12+9=21

the third side of a triangle must be equal to the two other sides added up to make it possible

also 15 if you're trying to make a possible right triangle

5 0
3 years ago
The General Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours
DerKrebs [107]

Answer:

Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

Step-by-step explanation:

H0 : σ² = 2.66²

H1 : σ² < 2.66²

X²c = (n - 1)*s² ÷ σ²

sample size, n = 40

Sample standard deviation, s = 1.9

X²c = ((40 - 1) * 1.9²) ÷ 2.66²

X²c = 140.79 ÷ 7.0756

X²c = 19.897

Using a confidence level of 95%

Degree of freedom, df = n - 1 ; df = 40 - 1 = 39

The critical value using the chi distribution table is 25.6954

Comparing the test statistic with the critical value :

19.897 < 25.6954

Test statistic < Critical value ; Reject the Null

Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

8 0
3 years ago
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