Answer:
A major arc (right figure) is an arc of a circle having measure greater than or equal to ( radians). SEE ALSO: Arc, Minor Arc, Semicircle.
Step-by-step explanation:
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
When X=Y every number on either side is the same, for example 1(X)=1(Y)
Step-by-step explanation:
This is because when X=Y the X value isn't altered in any way to equal Y, so they are the same number, hope this helped!
Answer:
one side is 40 other is 50
Step-by-step explanation:
perimeter=180cm
let one side=length=x
Acc. to condition:
other side=width=x+10 (one side exceed other by 10)
perimeter= 2(length+width)
subtitue all values given above:
180=2(x+x+10)
180=2(2x+10)
2x+10=180/2
2x+10=90
2x=90-10
2x=80
x=40
now
lenght=x=40cm
width=x+10=40+10
width=50cm