33 would round down. (30)
This is because the second 3 is smaller than 5 and when your rounding, if number your rounding is smaller then 5 you will round down
89 would round up. (90)
This is because the 9 is larger than 5 which means you would round up.
Please mark brainlies
If you follow PEMDAS
P-parentheses
E-exponent
M-multiplication
D-divide
a-addition
s-subtraction
then you should look in the parentheses and multiplying 3x should be your first step IF you know x
hope this helps :)
Given a quadratic equation

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.
In our case the coefficient of x is 10, so we write 10 as 2*5
2. then we write +

and -

to the expression:



Answer: