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TEA [102]
3 years ago
5

WILL GIVE BRAINLIEST

Mathematics
1 answer:
puteri [66]3 years ago
6 0

Step-by-step explanation:

{EF}^{2} =   {EG}^{2}   -  {FG}^{2}  \\  \\  =  {8}^{2}   -  {6}^{2}  \\  \\  = 64 - 36 \\  \\  = 28 \\  \\  \therefore \:  {EF} =  \sqrt{28}  \\  \\ \therefore \:  {EF} =  2\sqrt{7}  \\  \\  \sin \: E =  \frac{FG }{EG}  =  \frac{6}{8}  =  \frac{3}{4}  \\  \\   \huge\red {\boxed{\therefore \:  \sin \: E = \frac{3}{4}} } \\\sec \: G =  \frac{ EG}{FG}  =  \frac{8}{6}  =  \frac{4}{3}  \\  \\   \huge\purple {\boxed{ \therefore \: \sec \: G = \frac{4}{3}}} \\\\\cot \: G =  \frac{ FG}{EF}  =  \frac{6}{2\sqrt 7}  =   \frac{3}{\sqrt 7}  \\  \\  =   \frac{3\times\sqrt 7 }{\sqrt 7\times\sqrt 7 }  \\  \\  =   \frac{3\sqrt 7 }{ 7 }  \\  \\   \huge\orange {\boxed{ \therefore \: \cot \: G =  \frac{3\sqrt 7 }{ 7 } }} \\\\

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Someone pls help me with this and I’ll mark you as brainliest!!
MrRissso [65]

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2. I am pretty sure that it is right angles are congruent.

4. Angle O and R are congruent, never heard of their angles theorem but I think it might be related to CPCTC.

Step-by-step explanation:

Well a square is always used to represent a right angle so and both angle Q and N have squares and that should mean that they are both 90 degrees. Also while vertical angels are congruent, angles Q and N are not vertical from each other, Reflexive Property is if it is a side and not an angle I think.

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3 years ago
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Westkost [7]

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We can use vertical line test to determine if a relation is a function.

<em>If a vertical line passes the graph at any point only once, then the relation is a function, if there is even 1 line that passes the graph at 2 points, then it is NOT a function.</em>

<em />

The domain is the set of allowed x-values of the function. The range is the set of allowed y-values of the function.

  • Looking at the graph, we see that there are a lot of vertical lines that cuts the graph two times. Suppose x=3, x=4, x= 5 etc. So it is not a function.
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Correct answer is A

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3 years ago
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