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timurjin [86]
4 years ago
15

“which expression is the factored form of x^2-7x+10?”

Mathematics
1 answer:
mafiozo [28]4 years ago
4 0
(X-5)(x-2) here you go
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Segment AB is being dilated with the center at the origin. The image of A, point A" has coordinates of (3.2, 6.4). What is the s
insens350 [35]

Answer:  The correct option is

(A) The scale factor is 0.8 and the coordinates of point B" are (–3.2, –4.8).

Step-by-step explanation:  Given that the segment AB is being dilated to A''B'' with the center at the origin. The image of A, point A" has coordinates of (3.2, 6.4).

We are to find the scale factor of the dilation and the co-ordinates of the point B''.

From the given graph, we note that

the co-ordinates of point A are (4, 8).

Now, If S is the scale factor of dilation, then we must have

S\times (4,8)=(3.2,6.4)\\\\\Rightarrow (4S,8S)=(3.2,6.4)\\\\\Rightarrow S=\dfrac{3.2}{4}=\dfrac{6.4}{8}=0.8.

So, the scale factor is 0.8.

Now, the co-ordinates of point B are (-4, -6). So, the co-ordinates of B'' will be

(-4\times 0.8,-6\times 0.8)=(-3.2,-4.8).

Thus, the correct option is

(A) The scale factor is 0.8 and the coordinates of point B" are (–3.2, –4.8).

4 0
4 years ago
Read 2 more answers
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
The area of this figure is? sq meters
Ierofanga [76]

Answer:

The figure was not included in your question?

5 0
3 years ago
Need help i kinda suck at math
larisa [96]

Hi,

(4x−2)(3x^2−2x+1)

=(4x+−2)(3x^2+−2x+1)

=(4x)(3x2)+(4x)(−2x)+(4x)(1)+(−2)(3x2)+(−2)(−2x)+(−2)(1)

=12x3−8x^2+4x−6x^2+4x−2

=12x3−14x2+8x−2

Have a great day!

7 0
4 years ago
Please guys, can someone help me out?
balu736 [363]
Center point= 8 , 3
radius =7 Good luck!
5 0
3 years ago
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