Which expression correctly determines PR in triangle PQR?
1 answer:
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Answer:
The boxplots are on the figure attached. And the explanation is below.
Step-by-step explanation:
For the first formulation we have the following dataset:
1.76, 1.84, 2.71, 2.26, 3.15, 3.21, 2.48, 1.87
We can construct a box plot with the following R code:
> x1<-c( 1.76, 1.84, 2.71, 2.26, 3.15, 3.21, 2.48, 1.87)
> boxplot(x1,main="Boxplot method 1")
For the scond formulation we have the following data:
1.75, 2.08, 3.17, 3.21, 2.74, 2.83, 3.47, 2.47, 1.98
And the boxplot can be constructed with the following R code:
> x2<-c(1.75, 2.08, 3.17, 3.21, 2.74, 2.83, 3.47, 2.47, 1.98)
> boxplot(x2,main="Boxplot method 2")
And we can get the comparative 5 number results for each case:
> summary(x1)
Min. 1st Qu. Median Mean 3rd Qu. Max.
1.760 1.863 2.370 2.410 2.820 3.210
> summary(x2)
Min. 1st Qu. Median Mean 3rd Qu. Max.
1.750 2.080 2.740 2.633 3.170 3.470
As we can see both histograms shows asymmetrical distributions. For the first method Mean>Median so then we can conclude that the distribution would be approximately skewed to the right. For the second case the Median>Mean so we can conclude that the distribution would be approximately skwewed to the left.
