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3 years ago

12

Answer? I don’t understand any of this

1 answer:

9966 [12]3 years ago

7 0

$Answer:\\ Let\: x\: be\: the\: miles\: they\: run \\ \Rightarrow We \: have \: an \: equation:0.55x + 35 + 20 = 0.65x + 45 \\ \Leftrightarrow 0.65x + 45 = 0.55x + 55 \\ \Leftrightarrow 0.1x = 10\Leftrightarrow x = 100 \\ \Rightarrow The \: rental \: costs \: of\: both \: companies \: are \: the \: same \: at \: 100 \: miles$

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adult tickets to the fall play cost $8 and student tickets cost $4. the drama class sold 20 more adult tickets than student tick

andriy [413]

let us repersent the number of student tickets, then 's + 20' is repersenting the number of adult tickets.

The equation for the total tickets can be experssed as the following:

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3 years ago

HELP PLEASE!!! 10 PTS!!

allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD (Given)

$\angle ADC\cong \angle ACD$

$m\angle ADC=m\angle ACD$

According to the angle sum property, the sum of interior angles of a triangle is 180°.

$m\angle ADC+m\angle ACD+m\angle DAC=180$

$m\angle ACD+m\angle ACD+44=180$

$2m\angle ACD=180-44$

$2m\angle ACD=136$

Divide both sides by 2.

$m\angle ACD=68$

CE bisects ∠ACD.

$m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}$

$m\angle ACE=m\angle DCE=\dfrac{68}{2}$

$m\angle ACE=m\angle DCE=34$

Use angle sum property in triangle CDE,

$m\angle CDE+m\angle DCE+m\angle DEC=180$

$68+34+m\angle DEC=180$

$68+34+m\angle DEC=180$

$102+m\angle DEC=180$

Subtract 102 from both sides.

$m\angle DEC=180-102$

$m\angle DEC=78$

Therefore, the measure of angle DEC is 78°.

6 0

3 years ago