\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}
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Answer: 4
Step-by-step explanation:
(1 + 1) + (1 + 1)
2 + 2 = 4
Answer:
A
Step-by-step explanation:
Replace y with 0 and solve for x.
Exact Form: x = 3 + √2 , 3 −√2
Decimal Form: x = 4.41421356, 1.58578643
It is C and D
