Question

A submersible traveling at a depth of 250 feet dives at an angle of 15 degrees with respect to a

Answer 1

Answer:

$\boxed{\text{652 ft}}$

Step-by-step explanation:

The submersible is diving at a down angle of 15° along the hypotenuse AC of triangle ABC.  

Its horizontal track along the surface AB is 1500 ft.

$\begin{array}{rcl}\tan A & = &\dfrac{BC}{AC}\\\\\tan 15^{\circ} & = & \dfrac{a}{1500}\\\\0.2679 & = & \dfrac{a}{1500}\\\\a & = & 1500 \times 0.2679\\& = & \textbf{402 ft}\\\end{array}$

The submersible was already at a depth of 250 feet when it began the dive.

New depth = 250 + 402 = 652 ft

$\text{The depth after the dive is }\boxed{\textbf{652 ft}}$