Without speeding up it would take 5 1/3 seconds.. not sure if it speeds up in the question?
Answer:
The end behavior of f(x)=2/3x-2 is: as x->+ infinity, f(x)->+ infinity
as x->- infinity, f(x)->- infinity
Step-by-step explanation:
When you are asked about the end behavior of a function, look to see where the function is traveling on the graph. For instance, this graph is linear, so you should look to see if the slope is positive or negative. This linear function is positive, so as x is reaching positive infinity the f(x) would also be reaching positive infinity. As x is reaching negative infinity, f(x) would also be reaching negative infinity. The end behavior of a function describes the trend of the graph on the left and right side of the x- axis. (As x approaches negative infinity and as x approaches positive infinity).
The choices are supposed to be
f(x) = sin x + 3
f(x) = cos x + 3
f(x) = 3 sin x
f(x) = 3 cos x
The amplitude is the value of the numerical coefficient of sin or cos. The only possible answers are
f(x) = 3 sin x
f(x) = 3 cos x
Next, the function must pass through the point (0,3)
3 sin 0 = 0 and
3 cos = 3
Therefore, the answer is
f(x) = 3 cos x<span />
<h2><em>we can write (3x^2-5y^2) as (3x-5y)^2</em></h2><h2><em>(
3
x
−
5
y
)
2 as (
3
x−
5
y
)
(
3
x−
5
y
)</em></h2><h2><em>3
x
(
3
x
−
5
y
)
−
5
y
(
3x
−5
y
)</em></h2><h2><em>3
x
(
3
x
−
5
y
)
−
5
y
(3
x
−
5
y
)</em></h2><h2><em>3
x
(
3
x
)
+
3
x
(
−
5y
)
−
5
y
(
3
x
)
−
5
y(
-5
y
)</em></h2><h2><em>9
x
2
−
15
x
y
−
15y
x
+
25
y
2
</em></h2><h2><em> Subtract 15
y
x from −
15
x
y
.</em></h2><h2><em>9
x
2
−
30
xy
+
25
y
2</em></h2><h2><em> HOPE IT HELPS(◕‿◕✿) </em></h2><h2><em> SMILE!! </em></h2>
Answers:
Blank 1 = p and r
Blank 2 = corresponding angles converse
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Explanation:
Refer to the diagram below. I've marked lines p and r in red, and the angles 3 and 22 in blue. They are corresponding angles because they are both in the same southeast corner of their four-corner configuration.
If the corresponding angles are congruent, then the lines p and r are parallel by the aptly named corresponding angles converse