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1 answer:
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We have:
Thus:
Adding
gives:
Factoring gives:
Thus, we have:
or
.
Note that because
, there will be no solutions 
of the form 
for positive integer 
and solution 
. So we find the basic values of 
giving 
.
For with positive , 
(this can be seen easily from the unit circle. But 
, a contradiction. So we examine the case in which .
In this case,
. So this is the only solution to this equation.
Substituting this back in, we have
, as desired. So this is a valid solution.
Thus,.
Thus:
Adding
Factoring gives:
Thus, we have:
or
Note that because
For
In this case,
Substituting this back in, we have
Thus,
Answer:
C
Step-by-step explanation:
Let's check the first condition [y=110, t=0] for all the choices and eliminate:
A)
NO
B)
NO
C)
YES
D)
NO
E)
NO
Note: e^0 = 1
Only C is satisfied. But let's make sure the 2nd condition applies as well.
Hence, y approaches 30 as t goes to infinity. 2nd condition is satisfied as well.
Answer is C