Answer:
See the explanation
Explanation:
Answer 1.
As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.
Let S for short s for tall and W for white and w for purple allele.
So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,
................ Sw .................... sw
Sw ........ SSww ............. Ssww
sw ........ Ssww .............. ssww (tall and purple)
So from this 1/4 will be tall and purple while 3/4 will be short and purple.
In second case SSww only short purple progeny will appear.
Answer 2.
2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.
2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.
2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.
2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.
Hope this helps!
A compound that has Carbon and Hydrogen
An example of secondary pollutant is sulfurage
Answer:
50%
Explanation:
According to the given information, the woman has normal BRCA alleles while the man carries one copy of the mutated BRCA allele (BRCA1). A diploid organism such as human beings can have two BRCA alleles. A child gets one BRCA allele from the mother and the other from the father.
The child of the couple would get one normal allele from the woman. However, with respect to the BRCA allele, the man would form two types of gametes in equal proportion. The 50% of his gametes would have the mutated BRCA1 allele while the rest 50% would carry the normal BRCA allele. Therefore, the man can transmit either normal or mutated BRCA allele to the child. So, there are 50% chances for the child to get the mutated allele.
Answer:
<h2>The cells in a crosstab show summary data for the corresponding row and column, based on a measure and a summary function. The simplest crosstab is a frequency matrix, such as the following example, which shows the count of pets (measure) by gender (column) and species (row). Example of a simple crosstab</h2>
Explanation:
