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love history [14]

3 years ago

8

What is the value of x

1 answer:

I am Lyosha [343]3 years ago

3 0

the 2 equations are vertical angles, which mean they are equal to each other.

Set them to equal and solve for X:

x+40 = 3x

Subtract 1x from each side:

40 = 2X

Divide both sides by 2:

X = 40/2

X = 20

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28. Scott is participating in a monthly push-up challenge. Each day he is expected to increase the number of push-ups he complet

luda_lava [24]

Answer:

On day 5, he should be able to do 11

Step-by-step explanation:

Day 1 - 3

Day 2 - 5 (2 more than day before)

Day 3 - 7 (2 more than day before)

Day 4 - 9 (2 more than day before)

Following this pattern of +2, day 5 should be 11.

that's my thought process, so I hope it works

6 0

3 years ago

Simplify the first trigonometric expression by writing the simplified form in terms of the second expression (1/1-cosx)-(cos/1+c

garik1379 [7]

$(\frac{1}{1-cos(x)})-(\frac{cos(x)}{1+cos(x)})$

cscx is 1/sinx

maybe they want us to use pythagorean identity

$cos^2(x)+sin^2(x)=1$

I notice we have 1-cos(x) and 1+cos(x), if we multiply them, we get $1-cos^2(x)$

and if we look at the pythagorean identity and minus cos^2(x) from both sides, we get

$sin^2(x)=1-cos^2(x)$

since $csc(x)=\frac{1}{sin(x)}$ , $csc^2(x)=\frac{1}{sin^2(x)}=\frac{1}{1-cos^2(x)}$

(recall that (a-b)(a+b)=a²-b²)

match the denomenators of the original fraction

multiply first fraction by $\frac{1+cos(x)}{1+cos(x)}$ and the 2nd by $\frac{1-cos(x)}{1-cos(x)}$

$(\frac{1+cos(x)}{1-cos^2(x)})-(\frac{cos(x)(1-cos(x))}{1-cos^2(x)})=$

$((csc^2(x))(1+cos(x)))-((csc^2(x))(cos(x)-cos^2(x)))=$

$csc^2(x)+csc^2(x)cos(x)-(csc^2(x)cos(x)-csc^2(x)cos^2(x)=$

$csc^2(x)+csc^2(x)cos(x)-csc^2(x)cos(x)+csc^2(x)cos^2(x)=$

$csc^2(x)+csc^2(x)cos^2(x)=$

$csc^2(x)(1+cos^2(x))$ , hmm, to get ride of those cos(x)

look to the pythagorean identity again

$sin^2(x)+cos^2(x)=1$ , force one side into form 1+cos^2(x)

$1+cos^2(x)=2-sin^2(x)$ , recall that since csc(x)=1/sin(x), sin(x)=1/csc(x) and sin^2(x)=1/(csc^2(x))

$1+cos^2(x)=2-\frac{1}{csc^2(x)}$

subsituting

$csc^2(x)(1+cos^2(x))=$

$(csc^2(x))(2-\frac{1}{csc^2(x)})=$ distributing

$2csc^2(x)-\frac{csc^2(x)}{csc^2(x)}=$

$2csc^2(x)-1$ is the simplified expression

8 0

3 years ago

What divided by 6 equals 0.41?

dlinn [17]

2.46

I think.

Because if you multiply 6 and 0.41 you get 2.46.

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Eduardwww [97]

C is the correct answer

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Vilka [71]

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