All categories

2 years ago

A 'snail's pace is 60 inches per minute. At this rate how long will it take the snail to crawl 120 feet?

2 answers:

8 0

It will take 2 minutes because if a snail pace is 60 inches per minute means if you multiply 60 times 2 it will be 120 or you can add another 60 and it will give you 120

True [87]2 years ago

5 0

Ok, so here, we have the unit rate of the snail. Now, we need to set up a proportion.

60/1 = 120/x

Now, cross multiply.

60*x = 120*1

60x= 120

Now divide to solve for x.

60x/60 = 120/60
x = 120/60
x= 2

Now our final answer is 2.

Final answer:- The snail will take 2 minutes to crawl 120 feet

You might be interested in

Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.

d1i1m1o1n [39]

Answer:

Use the fact that sin(x) = opp/hyp and tan(x) = opp/adj

where opp=opposite, hyp=hypotenuse, adj=adjacent and recall sin(30)=1/2 and tan(30) = 1/sqrt(3)

sin(30) = 1/2 = 17/y

y = 17(2) = 34

tan(30) = 1/sqrt(3) = 17/x

x = 17sqrt(3)

So the answer is (d)

Note that you could have also use the Pythagorean theorem to find x instead of using tan(30).

4 0

2 years ago

Eight minus the product of two and a number x.

sergij07 [2.7K]

The number x is a -8

8 0

2 years ago

A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current

lapo4ka [179]

Using the z-distribution, we have that:

The hypothesis test is:

$H_0: \mu = 7.4$

$H_1: \mu < 7.4$

The p-value is of 0.0668.

The critical value is $z^{\ast} = -1.28$

b) Since the test statistic is less than the critical value for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

Item a:

At the null hypothesis, it is tested if the mean is of 7.4 minutes, that is:

$H_0: \mu = 7.4$

At the alternative hypothesis, it is tested if the mean is lower than 7.4 minutes, that is:

$H_1: \mu < 7.4$

We have the standard deviation for the population, hence, the z-distribution is used.

The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

$\sigma$ is the standard deviation of the sample.

n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 7.1, \mu = 7.4, \sigma = 1.2, n = 36$ .

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{7.1 - 7.4}{\frac{1.2}{\sqrt{36}}}$

$z = -1.5$

Using a z-distribution calculator, the p-value is of 0.0668.

Also using a calculator, considering a left-tailed test, as we are testing if the mean is less than a value, the critical value with a significance level of 0.1 is of $z^{\ast} = -1.28$ .

Item b:

Since the test statistic is less than the critical value for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

You can learn more about the use of the z-distribution to test an hypothesis at brainly.com/question/16313918

5 0

1 year ago

Help please ASAPP pleaseee

vagabundo [1.1K]

I think it’s the first option

6 0

2 years ago

9. What is the Greatest Common Factor (GCF) of 9 and 12? * 108 о O 36 o 9 3

Simora [160]

Answer:

Step-by-step explanation:

We found the factors and prime factorization of 9 and 12. The biggest common factor number is the GCF number. So the greatest common factor 9 and 12 is 3.

Hope this helps!

6 0

2 years ago