A^2+b^2=c^2 is known as the Pythagorean theorem. It is used to describe the relationship of the lengths of the sides of a right triangle.
The equation has one extraneous solution which is n ≈ 2.38450287.
Given that,
The equation;
![\dfrac{9}{n^2+1} =\dfrac{n+3}{4}](https://tex.z-dn.net/?f=%5Cdfrac%7B9%7D%7Bn%5E2%2B1%7D%20%3D%5Cdfrac%7Bn%2B3%7D%7B4%7D)
We have to find,
How many extraneous solutions does the equation?
According to the question,
An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.
To solve the equation cross multiplication process is applied following all the steps given below.
![\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B9%7D%7Bn%5E2%2B1%7D%20%3D%5Cdfrac%7Bn%2B3%7D%7B4%7D%5C%5C%5C%5C9%20%284%29%20%3D%20%28n%2B3%29%20%28n%5E2%2B1%29%5C%5C%5C%5C36%20%3D%20n%28n%5E2%2B1%29%20%2B%203%20%28n%5E2%2B1%29%5C%5C%5C%5C36%20%3D%20n%5E3%2B%20n%20%2B%203n%5E2%2B3%5C%5C%5C%5Cn%5E3%2B%20n%20%2B%203n%5E2%2B3%20-%2036%3D0%5C%5C%5C%5Cn%5E3%2B%203n%5E2%2Bn%20-33%3D0%5C%5C)
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y
with 0 and solve for x. The graph of the equation is attached.
n ≈ 2.38450287
Hence, The equation has one extraneous solution which is n ≈ 2.38450287
For more information refer to the link.
brainly.com/question/15070282
6/8ths are left you have to cross multiply to get the answer
The answer to that would be many
Answer:
The GCF is going to be 20
Step-by-step explanation:
This Is how I find the GCF of 2 numbers. I find the prime factorization first, then I find the common factors and multiply them. Here
The prime factorization of 20, 2 × 2 × 5= 20
The prime factorization of 80, 2 × 2 × 2 × 2 × 5 = 80
The common factors are 2, 2, and 5. We multiply those to get the GCF.
2 × 2 × 5 = 20