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Mrrafil [7]
3 years ago
13

Log3(7x) Use the Laws of Logarithms to expand the expression.

Mathematics
1 answer:
Bingel [31]3 years ago
7 0
Log3(7) + log3(x)
Terms that are multiplied inside one log become added when you separate them where each term gets its own log.
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Sandra's ice popsicle is 8 1/5 inches long. She eats 6 4/5 inches. How long is
pshichka [43]

Answer:1 2/5

Step-by-step explanation:

8 1/5 = 41/5

6 4/5 = 34/5

41/5 - 34/5 = 7/5 which is the same as 1 2/5

3 0
3 years ago
Read 2 more answers
A car travels 60 miles due north then makes a turn due west. It travels 72 miles west. How far is the car from its starting poin
Harlamova29_29 [7]

Answer:

93.7 miles

Step-by-step explanation:

This problem can be represented as a right angled triangle. The distance between the final point and the starting point is the hypotenuse.

We need to find the hypotenuse. We can use Pythagoras rule:

hyp^2 = opp^2 + adj^2

where opp = opposite side to the angle considered

adj = adjacent side to the angle considered

This implies that:

x^2 = 60^2 + 72^2\\\\x^2 = 8784\\\\x = \sqrt{8784} \\\\x = 93.7 miles

The car is 93.7 miles far from its starting point.

6 0
3 years ago
What is the slope of y = -2x and what does this mean?
olga_2 [115]

Answer:

-2 is the slope

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Inverse of y=14x2 show derivations
Rudik [331]
<h2>Answer:</h2>

f^{-1}  (x)=\sqrt{\frac{x}{14}}.

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expression.</h3>

y=14x^2

<h3>2. Substitute y for x, and x for y.</h3>

x=14y^{2}

<h3>3. Solve for y.</h3>

14y^{2}=x\\ \\y^{2} =\frac{x}{14} \\ \\y=\sqrt{\frac{x}{14}}

<h3>4. Express your result.</h3>

f^{-1}  (x)=\sqrt{\frac{x}{14}}.

4 0
1 year ago
The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?
Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

5 0
2 years ago
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