If 15 oranges cost Rs. 70,how much do 39 oranges cost ?

Mathematics

1 answer:

Minchanka [31]3 years ago

7 0

Answer:

firstly divide 70 by 15 and when the product came multiply it with 39

Step-by-step explanation:

70 ÷ 15 = 4.66

4.66 × 39 = 181.974

You might be interested in

Click and drag like terms onto each other to simplify fully.<br> 2-5+7y-5x+7x-2y

nikdorinn [45]

Answer: 5y + 2x - 3

(In simplest form)

6 0

3 years ago

Read 2 more answers

Five plus three equals

8_murik_8 [283]

Answer: 8

Step-by-step explanation:

5 chicken nuggets + 3 more chicken nuggets equals 8

5 0

3 years ago

Read 2 more answers

How many Solutions does this system have? (1 point)

mixas84 [53]

The given system of equation that is $2x+y=3$ and $6x=9-3y$ has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

$\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}$

Let us first bring the equation in standard form for comparison

$\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}$

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

In our case,

$a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3$

$a_{2} = 6, b_{2} = 3,\text{ and }c_{2} = -9$

$\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}$