36 feet okay it is 36 feet of the area
Answer:
24.75/24¾
Step-by-step explanation:
148.5 ÷ 6 = 24¾ or 24.75
Answer: Each driver drove 24.75/24¾ miles
Answer:
A
Step-by-step explanation:
We want to find the surface area, which will essentially just be the areas of all the figures given in the net.
We have two congruent triangles and 3 different rectangles.
<u>Triangles</u>:
The area of a triangle is denoted by: A = (1/2) * b * h, where b is the base and h is the height. The base here is 3 and the height is 4, so:
A = (1/2) * b * h
A = (1/2) * 3 * 4 = 6
Since there are two triangles, multiply 6 by 2: 6 * 2 = 12 cm squared
<u>Rectangles</u>:
The area of a rectangle is denoted by: A = b * h, where b is the base and h is the height.
The base of the leftmost rectangle is 4 and the height is 7, so:
A = b * h
A = 4 * 7 = 28
The base of the middle rectangle is 3 and the height is 7, so:
A = b * h
A = 3 * 7 = 21
The base of the rightmost rectangle is 5 and the height is 7, so:
A = b * h
A = 5 * 7 = 35
Add these together:
12 + 28 + 21 + 35 = 96 cm squared
The answer is thus A.
Answer:
x = -3
x = -1
x = 2
Step-by-step explanation:
The <u>zeros of a function</u> are the x-values of the points at which the curve crosses the x-axis.
From inspection of the given graph, the curve crosses the x-axis at:
Therefore, these are the zeros of the function.
check the picture below on the top side.
we know that x = 4 = b, therefore, using the 30-60-90 rule, h = 4√3, and DC = 4+8+4 = 16.
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=8\\ b=\stackrel{DC}{16}\\ h=4\sqrt{3} \end{cases}\implies A=\cfrac{4\sqrt{3}(8+16)}{2} \\\\\\ A=2\sqrt{3}(24)\implies \boxed{A=48\sqrt{3}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%0A%5Cbegin%7Bcases%7D%0Aa%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D8%5C%5C%0Ab%3D%5Cstackrel%7BDC%7D%7B16%7D%5C%5C%0Ah%3D4%5Csqrt%7B3%7D%0A%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B4%5Csqrt%7B3%7D%288%2B16%29%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D2%5Csqrt%7B3%7D%2824%29%5Cimplies%20%5Cboxed%7BA%3D48%5Csqrt%7B3%7D%7D)
now, check the picture below on the bottom side.
since we know x = 9, then b = 9, therefore DC = 9+6+9 = 24, and h = b = 9.
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=\stackrel{DC}{24}\\ h=9 \end{cases}\implies A=\cfrac{9(6+24)}{2} \\\\\\ A=\cfrac{9(30)}{2}\implies \boxed{A=135}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%0A%5Cbegin%7Bcases%7D%0Aa%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D6%5C%5C%0Ab%3D%5Cstackrel%7BDC%7D%7B24%7D%5C%5C%0Ah%3D9%0A%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B9%286%2B24%29%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D%5Ccfrac%7B9%2830%29%7D%7B2%7D%5Cimplies%20%5Cboxed%7BA%3D135%7D)
