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mixas84 [53]
4 years ago
6

If 15 oranges cost Rs. 70,how much do 39 oranges cost ?​

Mathematics
1 answer:
Minchanka [31]4 years ago
7 0

Answer:

  1. firstly divide 70 by 15 and when the product came multiply it with 39

Step-by-step explanation:

70 ÷ 15 = 4.66

4.66 × 39 = 181.974

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Given f(x) = 7|x + 41 - 3. Name the slope and vertex.
Molodets [167]

Answer:

Write the rule of the transformed function. Then graph at least three ... X {(x-2)-1. 1 y=-2. 1 X. Function in point slope form: y = Ź (*20). Function: V=-2 ... 4((x-3²-5). 4(~25) g(x)= 4(x-3) -20. 6. f(x) = 2 | 4x +3| + 7; translation 2 units ... 3 =0 mara 3(x+2x-8) c. Write the vertex for the parabola. f(3) =3(x-2)(x+4) ... x. Ty = x2 - 41

Step-by-step explanation:

3 0
3 years ago
Sellus
igor_vitrenko [27]

Answer:

3.9

Step-by-step explanation:

Given the data:

Payout ($) (x) : 0 2 4 8 10

Probability p(x) : 0.35 0.2 0.1 0.2 0.15

The expected winning ; E(X) = Σ(x * p(x))

Σ(x * p(x)) = (0*0.35)+(2*0.2)+(4*0.1)+(8*0.2)+(10*0.15)

= 0 + 0.4 + 0.4 + 1.6 + 1.5

= 3.9

8 0
3 years ago
Find the least common denominator of 1/2 and 3/5​
Scilla [17]

Answer:

10

Step-by-step explanation:

5/10, 6/10

5 0
3 years ago
Someone, please help i don't understand this
miv72 [106K]

Answer

62

5.3

65

5.8

2.5

Step-by-step explanation:

FOr the first one we have the opposite and adjacent side, so we'll use TOA

let x= angle

tan(x)=4.7/2.5

x=61.99 or 62

2.) for this one we can just use pathagoryeous thereom

2.5²+4.7²=c²

28.34=c²

c=5.323

3.) For this one we know that the angles in a traingle must add to 180

let x= missing angle

25+90+x=180

x=65

4.) For this one we have the adjacent side but need the hypotonouse

we will therefore use CAH

cos(25)=5.3/x

5.3/(cos(25))=x

x=5.8

5.) For this one we will just use the pathagoryeous to solve for the missing side

a²+5.3²=5.8²

a²=6.107

a=2.5

8 0
3 years ago
Compare using &lt;, &gt;, or =.<br> 4 5/8 _ 4 2/3
viktelen [127]

Answer:

<

Step-by-step explanation:

4 5/8 is smaller than 4 2/3

7 0
3 years ago
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