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irina1246 [14]
3 years ago
7

The vertex of this parabola is at (5, -4). Which of the following could be its equation? A.y = 2(x + 5)2 + 4

Mathematics
2 answers:
astraxan [27]3 years ago
4 0
I think d or b but if I am wrong sorry
Svetradugi [14.3K]3 years ago
3 0

Answer:

answer was D :)

Step-by-step explanation:

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F(x)=-7x2+8x+2 how many x-intercepts does the graph of f have
Lesechka [4]

The graph has 2 intercepts, as it is a parabola with a degree of 2.

6 0
3 years ago
The least common multiple of the numbers 15, 12, 8
Ymorist [56]

Answer: LCM of 8, 12, and 15 is 120.

Step-by-step explanation:

I hope this helps!

6 0
3 years ago
Read 2 more answers
Geometry // help with this pleaseeee ASAP
babunello [35]

Answer:

A:SPA =CFA by AA

Step-by-step explanation:

Hopefully this helps

6 0
3 years ago
The perimeter of a rectangular garden is 346. if the width of the garden is 79 feet, what is its length?
Nostrana [21]
Perimeter = L + L + W + W
346 = L + L + 79 + 79
346 = L + L + 158
346 - 158 = L + L  158 -158
188 = L + L
So im gonna square root 188
188 ( square rooted) = 13.7113092.....
Im gonna round it so the lengths gonna be 
≈ 13.7

6 0
3 years ago
A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors
mezya [45]
<h3>Answer:  491,891,400</h3>

Delete the commas if necessary.

============================================================

Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

  • 15 ways to pick the freshmen
  • 1287 ways to pick the sophomores
  • 70 ways to pick the juniors
  • 364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

7 0
2 years ago
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