The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Read more about trigonometry expressions at:

brainly.com/question/8120556

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3 0

2 years ago

The table and the graph each show a different relationship between the same two variables, x and y:

Gelneren [198K]

Answer:

110

Step-by-step explanation:

The answer is 110

If the function for the table is y=90x and the function for the graph is y=80x, then at x=11, the table would be at (11, 990) and the graph at (11, 880) meaning that the y value of the table would be 110 more than the y value of the graph.

4 0

3 years ago

The diagonal length is 16 and the length is 11 what is the width of this rectangle

allochka39001 [22]

Answer:

The answer is 176

Step-by-step explanation:

Multiply 16 by 11.

5 0

3 years ago

As an estimation we are told £3 is €4.

vova2212 [387]

Answer:

To solve the above problem we will use the unitary method as follows

As estimated If £ 3 is equivalent to € 4

Then, £ 1 will be equivalent to = € \frac{4}{3}

£ 64.60 will be equivalent to = € \frac{4}{3} \times 64.60 = 1.3333 \times 64.60 = 86.1311

Now you have to round the answer up to 2 decimal points to get the final answer

€ 86.1311 ≈ € 86.13

Thus, £ 64.60 is approximately equal to € 86.13.

Step-by-step explanation:

hope this helps if not let me now

3 0

2 years ago