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Papessa [141]
3 years ago
15

What are angles a,b,c,d ?

Mathematics
1 answer:
nevsk [136]3 years ago
7 0
I’m not sure but the answers maybe a = 101 b = 97 c = 83 d = 79
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The cost, in millions of dollars, for a company to manufacture x thousand speed boats is given by the function C(x) = 3x2 - 30x
nalin [4]

Answer:

  5000

Step-by-step explanation:

In vertex form, the cost function is ...

  C(x) = 3(x² -10x) +175 = 3(x² -10x +25) +175 -3(25)

  C(x) = 3(x -5)² +100

The vertex is at x=5, so the cost function will be minimized when 5000 speed boats are produced.

7 0
3 years ago
The functions f(x) and g(x) are described below: f(x) = 7x + 9 g(x) = 7x −4 The graph of g(x) is obtained by shifting down the g
Slav-nsk [51]
Correct Answer:
Option A

Solution:

f(x) = 7x + 9
g(x) = 7x - 4

We can re-write g(x) as:

g(x) = 7x + 9 - 13

Since 7x+9 is equal to f(x), we can write:

g(x) = f(x) - 13

This relation shows that g(x) is obtained by shifting f(x) 13 units vertically down. So the correct answer is option A.
6 0
3 years ago
Simplify 4/9 squared
belka [17]
4/81 (?) 
not sure if that is 100% correct 
6 0
3 years ago
Read 2 more answers
If x and y are both negative when is x-y positive
jarptica [38.1K]
Hmm

let's try some numbers

we have 3 scenarios
x>y
x=y
x<y

x>y
x=-1 and y=-2
x-y=-1-(-2)=-1+2=1
it's positive when x>y

x=y
x=-1, y=-1
-1-(-1)=-1+1=0
nope

x<y
x=-2 and y=-1
-2-(-1)=-2+1=-1
nope


x-y is positive when 0>x>y
4 0
3 years ago
Read 2 more answers
Can you please help me evaluate this problems
Fofino [41]

Answer:

16.   137

17.    89

18.   168

19.   50

20.  8

21.   96

22.   39

23.   5

24.   -2

25.   7

Step-by-step explanation:

We have to follow BODMAS which is the acronym for Bracket, Of, Division, Multiplication and Subtraction.

We have to perform our calculations in this order. i.e., Solve the calculations in a bracket first then of and so on.

a = 12; b = 9; c = 4

16. a² + b - c²          = (12)² + 9 - 4²      = 144 + 9 - 16 = 153 - 16      = 137

17. b² + 2a - c²        = 81 + 2(12) - 16    = 81 + 24 - 16 = 105 - 16      = 89

18. 2c(a + b)           = 2 · 4 (12 + 9)      = 8(21)                                  = 168

19. 4a + 2b - c²      = 4(12) + 2(9) - 4²  = (48 + 18 - 16 = 66 - 16       =  50

20. [a² ÷ (4b)] + c  = [12² ÷ 4(9)] + 4 = [144 ÷ 36] + 4 = 4 + 4          = 8

21. c²(2b - a)          = 4²(2(9) - 12) = 4²(18 - 12) = 16(6)                     = 96

22. [bc² + a] ÷ c     = [9(4²) + 12] ÷ 4 = [9(16) + 12] ÷ 4 = 156 ÷ 4     = 39

23. [2c³ - ab] ÷ 4   = [2(4)³ - 12(9)] ÷ 4 = [2(64) - 108] ÷ 4

                              = [128 - 108] ÷ 4 = 20 ÷ 4                                   = 5

24. 2(a - b)² - 5c   = 2(12 - 9)² - 5(4) = 2(3)² - 20 = 18 - 20              = -2

25. [b² - 2c²] ÷ [a + c - b]

                              = [9² - 2(4)²] ÷ [12 + 4 - 9] = [81 - 32] ÷ [16 - 9]

                             = 49 ÷ 7                                                                 = 7

8 0
3 years ago
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