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Nataly_w [17]
3 years ago
5

Help me with this pls AND PLS DONT DELETE THIS BECAUSE SOMEONE KEEPS DELETE MY QUESTIONS FOR NO REASONS PLZz help thanks :)

Mathematics
2 answers:
andreev551 [17]3 years ago
8 0
The answer to this question is c, if you count there are only 6 reds out of the 38
Phantasy [73]3 years ago
3 0

Answer:

your answer is B

Step-by-step explanation:

I hope this helps,

have a nice day/night

mark brainliest please

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Answer the question below in the image
konstantin123 [22]
A. total number of rolls: 100
probability to roll a 3: 11/100
5 0
3 years ago
A certain drink is made by adding 4 parts water to 2.5 part drink mix. What percent of the mixture is water? Omit % sign in your
Maru [420]

The mixture contains 61.5% of water.

<u>Step-by-step explanation:</u>

Total parts = 4+ 2.5 = 6.5

Parts of water =4

parts of drink = 2.5

Percent of water in the mixture = 4 × 100/ 6.5

                                                     = 400/6.5

                                                      = 61.53%

It is rounded to the nearest tenth as 61.5%.

8 0
3 years ago
Evaluate -16 - 9x<br> When x= 3
vfiekz [6]

Answer:

-43

Step-by-step explanation:

first we need to do 9x witch would be 9x3 so 9x3 is 27 now its down to -16 - 27 and that is -43

8 0
2 years ago
professor wrote the following inequalities for N number of students in his lecture. N &lt;10, N&gt;10, N&lt;22, N&gt;22. Turns o
m_a_m_a [10]

Answer:

There are N students in the class.

We know that ONLY ONE of the inequalities is true:

N < 10

N > 10

N < 22

N > 22

We want only one of these four inequalities to be true.

Remember that if we have:

x > y

y is not a solution, because:

y > y is false.

Then:

If we take N = 10, then:

N < 22

Is the only true option.

While if we take N = 22

N > 10

is the only true option.

So there are two possible values of N.

8 0
3 years ago
Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 12x^3-30x=5-2x^2
nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0

Now that we've factored our equation, we can use ZPP and break it up:

2x^2-5 = 0 \implies \\ 2x^2=5 \implies\\ x^2=\frac{5}{2} \implies\\ x=\pm\frac{\sqrt{5}}{\sqrt{2}}=\pm\frac{\sqrt{10}}{2} \\ \\ 6x+1 =0 \implies \\ 6x=-1 \implies\\ x=\frac{-1}{6}

So, our solutions are:

x\in \{\frac{\sqrt{10}}{2},-\frac{\sqrt{10}}{2},-\frac{1}{6}\}

4 0
3 years ago
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