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3 years ago

What is the length of bc?

Mathematics

1 answer:

weeeeeb [17]3 years ago

8 0

Pythagoraean theorem.
17^2=8^2+b^2
289=64+b^2
225=b^2
Sqrt(225)=b
B=15

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(n 4 - 2n 3 - 3n 2 + 7n - 2) ÷ (n - 2)

GrogVix [38]

I believe it's

- 1 - $\frac{4}{n - 2}$

Hope I helped! ( Smiles )

7 0

3 years ago

Read 2 more answers

8k + 2m = 3m + k<br><br> Solve for k

mina [271]

Minus both sides by 2m
$8k = 3 m - 2m + k \\ 8k = m + k$
Minus both sides by k
$7k = m$
Divided both sides by 7
$k = \frac{m}{7}$

6 0

3 years ago

Al llegar al hotel nos an dado un mapa con los lugares de la ciudad nos dijieron que 5 cm del mapa que representaban 600 metros

Sati [7]

Pregunta completa:

Al llegar al hotel nos an dado un mapa con los lugares de la ciudad nos dijieron que 5 cm del mapa que representaban 600 metros de la realidad hoy queremos ir a un par que que se encuentra a 8 cm del hotel en el mapa. ¿A qué distancia del hotel está la pareja?

Respuesta: 960m

Explicación paso a paso:

Dado que:

5 cm en el mapa equivale a 600 m en tierra Por lo tanto,

8 cm en el mapa será equivalente a:

5 cm en el mapa - - - - - -> 600 m en el suelo 8cm - - - - - - -> y metros en el suelo

Usando la multiplicación cruzada

y × 5 = 8 × 600

5y = 4800 Luego,

y = 4800/5

y = 960m

Por lo tanto, 8 cm en el mapa serán 960 m en realidad.

8 0

3 years ago

Can you do this because it is confusing to me

erica [24]

A cylinder is a three-dimensional structure formed by two parallel circular bases connected by a curving surface. The volume of the cylinder is 1330.4644 cm³.

<h3>What is a cylinder?</h3>

A cylinder is a three-dimensional structure formed by two parallel circular bases connected by a curving surface. The circular bases' centers overlap each other to form a right cylinder.

Given the height of the cylinder is 14 cm, while the diameter of the cylinder is 11 cm. Therefore, the volume of the cylinder can be written as,

The volume of the cylinder = (π/4)×(D²) × H

= (π/4)×(11)² × 14

= 1330.5 cm³

Hence, the volume of the cylinder is 1330.5cm³.

Learn more about Cylinder:

brainly.com/question/12248187

#SPJ1

3 0

2 years ago

Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9

taurus [48]

From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
$\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)$
and
$\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)$

Angle θ is given by
$\theta=180-M-N \\ \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)$

Given that a = 4 units, b = 5 units, and c = 9 units, thus
$\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)$

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
$\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\ \\ -4(x^2+81)+9(x^2-10x+41)=0 \\ \\ -4x^2-324+9x^2-90x+369=0 \\ \\ 5x^2-90x+45=0 \\ \\ x^2-18x+9=0 \\ \\ x=9\pm6 \sqrt{2}$

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
$x=9-6 \sqrt{2}=0.5147$

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.

6 0

3 years ago