60 cats out of 300 animals is .2 so the percent of cats is 20%
I did this quiz its Scenic Pathways has no sign up fee and a greater cost per day.
Answer:
The minimum sample size required is 207.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean <em>μ</em> is:
The margin of error of this confidence interval is:
Given:
*Use a <em>z</em>-table for the critical value.
Compute the value of <em>n</em> as follows:
![MOE=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=2.576\times \frac{29}{\sqrt{n}} \\n=[\frac{2.576\times29}{3} ]^{2}\\=206.69\\\approx207](https://tex.z-dn.net/?f=MOE%3Dz_%7B%5Calpha%20%2F2%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C3%3D2.576%5Ctimes%20%5Cfrac%7B29%7D%7B%5Csqrt%7Bn%7D%7D%20%5C%5Cn%3D%5B%5Cfrac%7B2.576%5Ctimes29%7D%7B3%7D%20%5D%5E%7B2%7D%5C%5C%3D206.69%5C%5C%5Capprox207)
Thus, the minimum sample size required is 207.
I was going to say that you would need to change the mixed numbers into an improper fraction but then I realized that they both have the same denominator (4), meaning that in this case if the whole number outside of the fraction is bigger than the one for the other then it’s greater than regardless.
6 is greater than 5, so
5¾<6¼
Answer:
Some students were asked how many books they were carrying in their backpacks. The data is given in this frequency table. What is the mean number of pens carried by these students in their backpacks?
Pens Frequency
0 4
1 5
2 8
3 4
4 3
5 1
A.2
B.3.5
C.4
D.5.5
