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3 years ago

Point A is located at (-2, 4). After it is transformed, point A' is located at (2, 4). What could the transformation be?

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

4 0

The only one that wouldn’t change the y-value is a reflection across the y-axis.

fredd [130]3 years ago

3 0

I wrote zones but then noticed that we actually don't need :p

The answer is "a reflection in the y-axis"

Hope it helps!

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A certain process for removing copper from copper bearing ore had been in use for a period of time, and it is known that this pr

Anika [276]

Answer:

d. Ore treated with the new process.

Step-by-step explanation:

This is a common practice in statistics, in which we use a sample of a population to infer something about the entire population. We should use a sample of 100.

For example, if we want to know the proportion of residents of Buffalo, New York, who are Bills fans, we are going to take a sample of like, 100 residents, and then use this to estimate for the entire city.

In this problem, we have that:

A new process that is supposed to increase the recovered amount is being tested. In a simple random sample of 100 batches of ore, an average of 42 pounds per ton were recovered using the new process.

So the population of interest is the ore treated with new process. We use a sample of 100 to gather information about the entire population.

So the correct answer is:

d. Ore treated with the new process.

5 0

3 years ago

Please I need help with differential equation. Thank you

Inga [223]

1. I suppose the ODE is supposed to be

$\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)$

Solving for $\dfrac{\mathrm dy}{\mathrm dt}$ gives

$\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}$

which is undefined when $t=\pm1$ . The interval of validity depends on what your initial value is. In this case, it's $t=-\dfrac12$ , so the largest interval on which a solution can exist is $-1\le t\le1$ .

2. Separating the variables gives

$\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}$

Integrate both sides. On the left, we have

$\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}$

where we substituted $z=y^{1/2}$ - or $z^2=y$ - and $2z\,\mathrm dz=\mathrm dy$ - or $\mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}$ .

$\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)$

On the right, we have

$\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)$

$\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C$

$2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C$

$\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C$

$y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}$

$y^{1/2}=C(1-t^2)^{1/4}-1$

I'll leave the solution in this form for now to make solving for $C$ easier. Given that $y\left(-\dfrac12\right)=1$ , we get

$1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1$

$2=C\left(\dfrac54\right)^{1/4}$

$C=2\left(\dfrac45\right)^{1/4}$

and so our solution is

$\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}$

3 0

3 years ago

Triangles ABC and EDC are similar . find the measure of angle D.

ratelena [41]

Since you are given that the triangle are similar, by definition of similar, we know that corresponding angles are congruent and corresponding sides are proportional.
The ORDER of the similarity statement is paramount.
Triangle ABC is similar to triangle EDC means that:
Angle A = Angle E
Angle B = Angle D
Angle C = Angle C

Angle B = 62 degrees so Angle D = 62 degrees.

4 0

3 years ago

Tricia had 4 1/8 yards of fabric to make curtains. When she finished she had 2 3/8 yards of fabric left. She said she used 2 2/8

lora16 [44]

4 1/8 - 2 3/8= (3 9/8-2 3/8)=1 6/8

2 2/8+ 2 3/8= 4 5/8
no
If she used 2 2/8 yards of fabric she should have 1 6/8 left not 2/38
She would have had to bought 4 5/8 yards of fabric to have 2 2/8 left.

6 0

3 years ago

I need help plz help

grin007 [14]

Answer:

12,6,0,-6,-12

Step-by-step explanation:

Plug the x values into the equation

y=-3x

y=-3(-4)=12

y=-3(-2)=6

y=-3(0)=0

y=-3(2)=-6

y=-3(4)=-12

4 0

3 years ago