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3 years ago

Verbal expression for 5 little 2 at the top

Mathematics

1 answer:

Ivenika [448]3 years ago

6 0

Do you mean 5^2? its called 5 to the second power. Hope this answers your question! :)

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Suppose the function of h is defined, for all real numbers as follows: (f) x = -3 if x is <) 3 if x is =0 -2 if x is > 0

V125BC [204]

Answer:

See explanation

Step-by-step explanation:

The question is not properly presented; I will answer this with the following similar question.

$h(x) = -\frac{1}{3}x^2 + 4$ --- $x \ne 2$

$h(x) = -4$ --- $x= 2$

Required

$h(-5)\ \&\ h(2)$

<u>Calculating h(-5)</u>

This implies that: x = -5

$-5 \ne 2$

So, we make use of:

$h(x) = -\frac{1}{3}x^2 + 4$

Substitute -5 for x

$h(-5) = -\frac{1}{3} * (-5)^2 + 4$

$h(-5) = -\frac{1}{3} * 25 + 4$

$h(-5) = -\frac{25}{3} + 4$

Take LCM

$h(-5) = \frac{-25+12}{3}$

$h(-5) = -\frac{13}{3}$

<u>Calculating h(2)</u>

This implies that: x = 2

$2 = 2$

So, we make use of:

$h(x) = -4$

Substitute 2 for x

$h(2) = -4$

<em>Use the above explanation to answer your question</em>

3 0

3 years ago

The radius of a circle is 19 kilometers. What is the circle's area?

Firdavs [7]

<h2> <em>Answer</em></h2>

<em>361</em><em>π</em><em>km²</em>

<h2> <em>Explanation</em></h2>

• the formula to find the area of a circle is A=πr²

<h3> => <em>A=π(19km)²</em></h3><h3><em>A=π(19km)² => A=361πkm</em>²</h3><h2><em>I</em><em> hope</em><em> it</em><em> helps</em><em>!</em><em>!</em></h2>

4 0

3 years ago

Find the 84th term of the arithmetic sequence -5,15,35, ...

pav-90 [236]

Answer:

The 84th term of the arithmetic sequence -5,15,35, ... is 1675.

Step-by-step explanation:

The arithmetic sequence -5,15,35, ... increases by 20 per term. Add 20 to the prior term to find the new term. Do this 83 times from -5, and you reach 1675.

8 0

3 years ago

A piece of wire of length 5050 is cut, and the resulting two pieces are formed to make a circle and a square. Where should the

algol [13]

Answer:

x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

Step-by-step explanation:

Let x be the length of wire that is cut to form a circle within the 5050 wire, so 5050 - x would be the length to form a square.

A circle with perimeter of x would have a radius of x/(2π), and its area would be

$A_c = \pir^2 = \pi (\frac{x}{2pi})^2 = \frac{x^2}{4\pi}$