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nikklg [1K]
3 years ago
10

The perimeter of a rectangular playground shown is 140 feet what is the area of the playground if the length is 40 feet

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
This will leave you with

140 = 2(40) + 2x

60 = 2x

30= x



So the length is 30.
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Material for a dress costs £5.50 per metre.<br> find the cost of 10cm and 70cm
Zielflug [23.3K]

Answer:

<em>The cost of 10 cm and 70 cm are  £0.55 and £3.85 respectively.</em>

Step-by-step explanation:

Material for a dress costs £5.50 per meter.

We know that,  <u>1 meter = 100 cm</u>.

Suppose, the cost of 10 cm material is x and the cost of 70 cm material is y

Now, <u>according to the ratio of "cost" to the "length of material"</u> , we will get.......

\frac{x}{10} =\frac{5.50}{100}\\ \\ 100x=10*5.50=55\\ \\ x=\frac{55}{100}=0.55

and

\frac{y}{70} =\frac{5.50}{100}\\ \\ 100y=70*5.50=385\\ \\ x=\frac{385}{100}=3.85

So, the cost of 10 cm material is £0.55 and the cost of 70 cm material is £3.85

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3 years ago
What is the inverse function of 15x + 14
Hitman42 [59]
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3 years ago
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vodka [1.7K]

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Step-by-step explanation:

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3 years ago
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There are 20 students in a math class. Thirty percent of the
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

20% of 30 is 6 are randomly selected.

30 choose 6 = 30! / (30-6)! 6!

                 = 30! / 24!6!

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                   --------------------------------- <-- 24! cancels

                    6 * 5 * 4 * 3 * 2 * 1

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                  ---------------------------------- <--- 30 = 6 * 5 cancels

                      4 * 3 * 2 * 1

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3 0
2 years ago
Q1.Simplify:
solniwko [45]

\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\

\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\

\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2}  \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625

6 0
2 years ago
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