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3 years ago

10

Find a value of k such that kx2 + 12x − 4 = 0 has one real-number solution. Explain.

2 answers:

Allisa [31]3 years ago

8 0

The answer is 0.6!

Explanation

Marta_Voda [28]3 years ago

5 0

Answer: if x is to the 2 power then

kx^2+12x-4=0 Add 4 to the both sides

kx^2+12x=4 Divide both sides by 12

kx^2=1/3x square root the both sides

k=0.6x

Step-by-step explanation:

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