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lbvjy [14]
3 years ago
10

Find a value of k such that kx2 + 12x − 4 = 0 has one real-number solution. Explain.

Mathematics
2 answers:
Allisa [31]3 years ago
8 0
The answer is 0.6!

Explanation
Marta_Voda [28]3 years ago
5 0

Answer: if x is to the 2 power then

kx^2+12x-4=0         Add 4 to the both sides

kx^2+12x=4             Divide both sides by 12

kx^2=1/3x                square root the both sides

k=0.6x

Step-by-step explanation:

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