
<h2>Given :- </h2>
- wide of the hall (Breadth) = 10m
<h2>To Find :- </h2>
- Surface area of the walls (Four walls area)
<h2>Formula :- </h2>
Four walls area of the hall = 2h(l+b)
where,
<h2>Solution : - </h2>
By substituting values according to the formula,
➙ 2 × 4m(12m + 10m)
➙ 8m(22m)
➠ 176m²
It's option B
<h3><u>Hence, The surface area of the walls is (B) 176m²</u></h3>
<h2 /><h2 />
-0.04 less than <span>-0.050</span>
Answer:
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Step-by-step explanation:
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