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Allushta [10]
3 years ago
6

Which of the following helps bloggers decide how to present information

Mathematics
2 answers:
bekas [8.4K]3 years ago
8 0
Since there is no options, i will list several reasons that help bloggers decide how to present information :
- Audience expectation
- Blogger's point of view and personal principle
- The actual fact that blogger has
sergejj [24]3 years ago
7 0

How they want their audience to interact with the blog ~Apex

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What are the lcm of 4,2,4
Delicious77 [7]

The least common multiple of  2  and  4  is  4 .

Here's a useful hint to keep in mind:
If the smaller number is a factor of the larger number,
then the larger number is the LCM of both of them.



5 0
3 years ago
Read 2 more answers
10 + 4x = 6<br> I would like to find the equation
sp2606 [1]

Answer:

4x=6-10

4x=-4

x=-4÷4

x=-1

8 0
3 years ago
Read 2 more answers
The initial cost to drill a well is $210000. the daily rate to operate the well is $500. The current selling price is $65 per ba
SVETLANKA909090 [29]

Hi there!

There is an initial cost of $210,000 (which you're just going to pay once)

Then it costs $500 per day to operate.

The number of days is represented by "x".


Your equation in function notation should look like this :

f(x) = 500x + 210,000


There you go! I really hope this helped, if there's anything just let me know! :)

8 0
3 years ago
Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0
3 years ago
Taylor dropped a rubber ball from a height of 8 feet.The ball hit the ground after 1 second,bounced up to 5 feet in the next sec
Rzqust [24]

Answer:

The graph is constant in the interval [4,6]

Step-by-step explanation:

We are given that,

Taylor dropped a rubber ball from a height of 8 feet.

So, at time t= 0 sec, the ball is being thrown.

Now, the next events follows as below:

1. After a second, the ball hits the ground.

2. It bounces up to 5 feet in the next second.

3. The ball again hits the ground in the next second.

4. Now, the ball again jumps up to height 2.5 feet, when Taylor holds the ball for 2 seconds more.

So, we get the figure given below, we see that,

The graph is constant in the interval [4,6].

3 0
3 years ago
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