If -5/2 is a root of that 3rd degree polynomial, then when we do synthetic division on it we will get a remainder of 0, and the resulting numbers from our math will then become the coefficients to a new polynomial, one degree less than what we started with, called the depressed polynomial. Put -5/2 outside the "box" and the coefficients inside: -5/2 (2 7 1 -10). Bring down the
2 and multiply it by -5/2 to get -5. Put that -5 up under the 7 and add to get
2. Multiply that 2 by the -5/2 to get -5. Put that -5 up under the 1 and add to get
-4. Multiply that by -5/2 and get 10. Put that 10 up under the -10 and add to get a remainder of 0. Those bolded numbers now are the coefficients of our new polynomial, one degree less than what we started with. That polynomial is
. Now we need to factor that to find the other 2 roots to our polynomial. If we factor a 2 out we have
,That factors easily to 2(x+2)(x-1). That gives us x+2=0 and x = -2, x-1=0 and x = 1. The 3 solutions or zeros or roots are -5/2, -2, 1. There you go!
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
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Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e. 
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587
It would the answer C choice
Answer:
2x-z=0 is the equation of the plane.
Step-by-step explanation:
Given that the plane passes through the points (1,0,2) and (-1,1,-2)
and also origin.
Hence equation of the plane passing through three points we can use
Any plane passing through 3 given points is given as
![\left[\begin{array}{ccc}x-x_1&y-y_1&z-z_1\\x_2-x_1&y_2-y_1&z_2-z_1\\x_3-x_1&y_3-y_1&z_3-z_1\end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx-x_1%26y-y_1%26z-z_1%5C%5Cx_2-x_1%26y_2-y_1%26z_2-z_1%5C%5Cx_3-x_1%26y_3-y_1%26z_3-z_1%5Cend%7Barray%7D%5Cright%5D%20%3D0)
Substitute the three points to get
![\left[\begin{array}{ccc}x-1&y&z-2\\-1-1&1&-2-2\\0-1&0&0-2\end{array}\right] \\=0\\(x-1)(-2) -y(4-4)+(z-2)(1) =0\\-2x+z=0\\2x-z-=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx-1%26y%26z-2%5C%5C-1-1%261%26-2-2%5C%5C0-1%260%260-2%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D0%5C%5C%28x-1%29%28-2%29%20-y%284-4%29%2B%28z-2%29%281%29%20%3D0%5C%5C-2x%2Bz%3D0%5C%5C2x-z-%3D0)
2x-z=0 is the equation of the plane.
