For number 16 we need to write the data as a ratio then convert to a unit rate (amount per 1)...
308/14 = x/1
Cross multiply
14x = 308
x = 308/14
x = 22
So the fuel efficiency is
22 miles per 1 gallon or
22/1
For number 17, since the car was driven at 48 mph, we just have to divide distance driven by speed to get how long it took...
288 miles ÷ 48 mph =
6 hours
Answer:
-6/5
Step-by-step explanation:
slope =coefficient of x
Answer:
We are given an area and three different widths and we need to determine the corresponding length and perimeter.
The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards. This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.
The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards. This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.
The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10. This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.
Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.
<u><em>Hope this helps!</em></u>
Answer: her call lasted for 44 minutes
Step-by-step explanation:
Linda purchase a prepaid phone card for $30. This means that the credit on her card is $30.
Long distance calls cost $0.17 each. Linda use her card only to make a long distance call. Assuming she made a total of x minutes of long distance calls, the cost would be $0.17x. The amount remaining on her card will be
30 - 0.17x
if the remaining credit on her card is $22.52, the number of minutes,x that the call lasted will be
22.52 = 30 - 0.17x
0.17x = 30 - 22.52
0.17x = 7.48
x = 7.48/0.17 = 44
4x^2 + 5xy - y^2 = 6
Implicitly differentiating both sides,
4(2x) + 5(x y' + y) - 2yy' = 0
where y' = dy/dx
8x + 5xy' +5y -2yy' = 0
combining y' terms
y' (5x-2y) +8x +5y = 0
y'(5x-2y) = -(8x+5y)
dy/dx = -(8x+5y)/(5x-2y)
or
dy/dx = (8x+5y)/(2y-5x)
