Question

What are the coordinates of the terminal point for 0=5pie/6

Answer 1

Answer:

P($\frac{5\pi }{6}$) = ( -$\sqrt{3} / 2$ , $1/2$ )

Step-by-step explanation:

Cos $\frac{5\pi }{6}$ = $\sqrt{3} / 2$

Sin $\frac{5\pi }{6}$ = $1/2$

Since $\frac{5\pi }{6}$ lies in Quadrant II , So Cos $\frac{5\pi }{6}$ < 0, Sin $\frac{5\pi }{6}$ > 0

So,

The coordinates are P($\frac{5\pi }{6}$) = ( -$\sqrt{3} / 2$ , $1/2$ )

Answer 2

Answer:

$p(\frac{5 \pi}{6} ) = (- \frac{\sqrt{3} }{2} , \frac{1}{2} )$

Step-by-step explanation:

$cos(\frac{5 \pi}{6} )=\frac{\sqrt{3} }{2}$

$sin(\frac{5 \pi}{6} ) = \frac{1}{2}$

(5π)/6 is in quadrant II, so..

$cos(\frac{5 \pi}{6} ) < 0$

$sin(\frac{5 \pi}{6} ) > 0$

The points are:

$p(\frac{5 \pi}{6} ) = (- \frac{\sqrt{3} }{2} , \frac{1}{2} )$