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ser-zykov [4K]
3 years ago
12

Solve 3[-x + (2 x + 1)] = x - 1.

Mathematics
1 answer:
Viktor [21]3 years ago
4 0
The answer is -1. First you distribute the 3. Then u distribute the 3 again to the parentheses. Then solve it from there

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Find the greatest possible error for each measurement 1 1/4c
Vikki [24]

Answer:

0.5

Step-by-step explanation:

6 0
3 years ago
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Help AB and CD are straight lines find z​
chubhunter [2.5K]

Answer: z=16

Step-by-step explanation:

Angles on a straight line add up to 180.

As AB is a straight line we can use that to help us find z.

So you would do 68+85+11=164 (I got the 11 from the angle trapped between like C and F as opposite angles are the same).

Then you would do 180-164=16

So z=16

Hope this helps :)

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Let f(x)=3x2 +4 and let g (x)= x+2<br> find (f+g) (x).
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3 years ago
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Find Distance (4,6) (-4,-3)​
vampirchik [111]

Answer:

\sqrt{145}

Step-by-step explanation:

The distance formula states that the distance between two points (a,b) and (c,d) is \sqrt{(a-c)^2+(b-d)^2}.

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\sqrt{(4-(-4))^2+(6-(-3))^2.

Simplifying with order of operations, first using the distributive property, gives

\sqrt{(4+4)^2+(6+3)^2.

Squaring and adding gives

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which is the answer in simplest form. This also rounds to about 12.04.

7 0
2 years ago
The midpoint of AB is M(3, -1). If the coordinates of A are (5,1), what are the
Vera_Pavlovna [14]

Given parameters:

Midpoint of AB =  M(3, -1)

Coordinates of A = (5,1)

Unknown:

Coordinates of B = ?

Solution:

To find the mid point of any line, we use the expression below;

              x_{m}   = \frac{x_{1} + x_{2}  }{2}    and y_{m}  = \frac{y_{1} + y_{2}  }{2}

where x_{m}  and y_{m} = coordinates of the mid points = 3 and -1

   x₁  = 5 and y₁ = 1

  x₂ = ?  and y₂ = ?

Now let us input the variables and solve,

            3  = \frac{5 + x_{2} }{2}           and     -1 = \frac{1 + y_{2} }{2}

    5 +  x₂  = 6                          -2 = 1  + y₂

            x₂ = 1                             y₂ = -2 -1 = -3

The coordinates of B = 1, -3

6 0
3 years ago
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