Ask question

Ask question

All categories

3 years ago

8

For the graphed exponential equation, calculate the average rate of change from x = −2 to x = 1.

2 answers:

marishachu [46]3 years ago

8 0

At x = -2, y = -4
At x = 1, y = 3
You have two pairs (1,3)(-2,-4).
You have to figure out the rate of change
(y2-y1)/(x2-x1)
(-4-3)/(-2-1)
Which the answer is b 7/3 hope this helps.

blagie [28]3 years ago

3 0

At x = -2, y = -4
At x = 1, y = 3
This gives you two ordered pairs (1,3) and (-2,-4).
Use the slope formula to find slope(rate of change)
(Y2-y1)/(x2-X1)
(-4-3)/(-2-1)
M = -7/-3 = 7/3

You might be interested in

Which point could represent 5 3 ?

Fittoniya [83]

Answer:

the answer is c

Step-by-step explanation:

i just finished the lesson

7 0

3 years ago

Read 2 more answers

Toms son works in a sports store.Toms son earns a commision. He makes 2.5% of the amount he sells. Last week he sold $900 worth

siniylev [52]

Answer:

22.5

Step-by-step explanation:

2.5/100= 0.0250

0.025 x 900 = 22.5

5 0

3 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

3 years ago

Helppp meeee please

IrinaK [193]

Answer:

True.

Step-by-step explanation:

It would be better if it was clearer, but I stand by my answer. "True".

6 0

2 years ago

Joe walked 4/9 of a mile in 4/5 of an hour. What is his unit rate in miles per hour? 4/9 over 4/5 = 5/9 mile per hour 4/5 over 4

Vilka [71]

<span>divide 4/9 by 4/5 is your answer</span>

8 0

3 years ago

Read 2 more answers