The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
= 
(-)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -x + 3
y = -.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
Answer:
Step-by-step explanation:
At this price, the store sells 100 men's hats per week. The owner estimates that for every $1 increase in price, one fewer men's hat is sold per week
Answer:
dude bace times hight 4×2×3
Answer:
Step-by-step explanation:
You'll divide the tip by the sub-total and multiply by 100
7/52.99 *(100) =13.21%
Answer:
Step-by-step explanation:
The first expression has value 12
The second expression has value -6
The third expression has value
4
And finally the forth expression has value 1.14
((13 + 7) = 20
(12+4) = 16
16/ (20 - 16)= 16 / 4
16/4 = 4
