F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
Answer:
(x+9)(x+2)
Step-by-step explanation:
x(x+9)+2(x+9)
(x+2)(x+9)
the order of the (---) doesn't matter
Given:
The function given is,
Required:
To graph the given function.
Explanation:
We have the given function as follows:
The graph of the function is shown below in the attachment:
Final Answer:
The graph of the function is shown in the attachment.
Answer: yes.
Step-by-step explanation:
adding 10 is moving the decimal point once to the right, so yes.
move the decimal point in 0.007 once to the right (multiply it by 10) and you get 0.07
Answer:
c(4) = -76
Step-by-step explanation:
c(x) x=4 so plug 4 in for x
-5(4)² + (4)
Do parentheses first so... 4² = 16
-5(16) + 4
-5(16) = -80
-80+4 = -76
c(4) = -76
