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IgorC [24]
3 years ago
8

Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options.

Mathematics
2 answers:
Kryger [21]3 years ago
8 0

Answer:

The first, second, and fifth statements are correct.

Step-by-step explanation:

We are given a circle with the equation:

x^2+y^2-2x-8=0

And we want to select the statements that are true.

First, we can convert the equation into standard form. We can group each variable:

(x^2-2x)+(y^2)=8

And complete the square for the first term:

(x^2-2x+1)+(y^2)=8+1

Factor and simplify:

(x-1)^2+y^2=9

We can rewrite our equation as:

(x-(1))^2+(y-(0))^2=(3)^2

So, this tells us that we have a circle centered on (1, 0) with a radius of 3 units.

In this case, the first statement, second statement (the point (1,0) is on the x-axis), and fifth statements are correct (the square root of 9 is also 3).

Tcecarenko [31]3 years ago
5 0

Answer:

The first, second, and fifth statements are correct.

Step-by-step explanation:

i got it right on edg if right mark as brainliest

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