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3 years ago

How many values are within the limits 100 and 150

1 answer:

7 0

It really depend what they are taking about because with decimals there are infinite numbers between those numbers but if they are saying just whole numbers like(1,2,3,4,5) then 50 including the numbers given

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An object has a potential energy of 14 J and a mass of 17 kg , how far above the ground is the object? An object moving with a s

victus00 [196]

1. Potential Energy = mgh

h = U_g / (mg) = 14 / (17 * 9.81) = 0.084 m above the ground.

2. Kinetic Energy = 1/2 mv^2

m = 2K_e / (v^2) = 2.45 kg

3. U_g = mgh = (1200)(9.81)(24) = 282528 J

4. U_g = mgh = (478)(9.81)(150) = 703377 J

5. U_g = mgh = (100)(9.81)(12.5) = 12262.5 J

6. h = U_g / (mg) = 14 / (17 * 9.81) = 0.084 m above the ground.

7. m = U_g / (gh) = 1500 / (9.81 * 35) = 4.37 kg

3 0

3 years ago

Evaluate 14 + (-8) ÷ 2 · -3. -9 15 26 -30

Rudiy27

For this case we must evaluate the following expression:

14 + (- 8) ÷ 2 * -3

According to the method of algebraic resolution, called PEMDAS, the divisions and multiplications must be made from left to right, before the addition and subtraction, then:

14 + (- 4) * - 3 =

We eliminate the parenthesis keeping in mind that $- * - = +$

$14 + 12 =$

Equal signs are added and the same sign is placed:

$14 + 12 = 26$

Answer:

7 0

3 years ago

What is the answer for 4i over 3+7i

icang [17]

Answer:

see explanation

Step-by-step explanation:

given $\frac{4i}{3+7i}$

To rationalise multiply the numerator/denominator by the conjugate of the denominator

the conjugate of 3 + 7i is 3 - 7i, hence

$\frac{4i(3-7i)}{(3+7i)(3-7i)}$

distribute the numerator/denominator

= $\frac{12i-28i^2}{9-49i^2}$

[ note that i² = - 1 ]

= $\frac{12i+28}{9+49}$

= $\frac{28+12i}{58}$

= $\frac{28}{58}$ + $\frac{12}{58}$ i

= $\frac{14}{29}$ + $\frac{6}{29}$ i ← in standard form

6 0

3 years ago

BROOO HELP what is the slope of the line through (-3,3) and (-1,-1)?

lesya [120]

Answer:

Step-by-step explanation:

To find the slope between any two points, we can use the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Where (x₁, y₁) and (x₂, y₂) are two, separate points.

We have the two points (-3, 3) and (-1, -1).

So, let (-3, 3) be (x₁, y₁) and let (-1, -1) be (x₂, y₂).

Substitute them into the slope formula to get:

$m=\frac{-1-3}{-1-(-3)}$

Subtract:

$m=\frac{-4}{2}=-2$

Hence, our slope is -2.

So, our answer is C.

6 0

2 years ago

Read 2 more answers

When an object with a momentum of 80 kg ´ m/s collides with an object with a momentum of –100 kg ´ m/s the total momentum after

mojhsa [17]

This is a physics problem.

The law is that the momentum is preserved: total momentum before collsion = total momentum after collision

Momentum before collision = 80 kg.m/s - 100 kg.m/s = -20 kg.m/s

Then answer is b. - 20 kg.m/s

3 0

2 years ago