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2 years ago

What is 85.807 rounded to the nearest tenth?

Mathematics

2 answers:

MissTica2 years ago

5 0

85.8 the 0 makes you stay the same

Llana [10]2 years ago

5 0

Answer:

85.8

Step-by-step explanation:

85.8<u>0</u>7. The 8 in bold is the tenth place and the 0 underlines is the determining factor on if you round up. Whenever you're looking to round up always loo at the number behind the value needed to round up. If the number in this case 0, is less than 4 you do not round up. If the number behind the value is 5 or above, then you round up. 0 is less than 4.

Hope it helps!

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Which of the following is true about the graph of f(x)=7^x. Select all that apply.

marishachu [46]

Answer:

Step-by-step explanation:

If it intersects the x axis, then y = 0. This is not possible, as you can plug in x to be 1/100000000000000000000000000000000000, or something very tiny, but it will never get 0. So, A is not a choice.

This also means B is not a choice.

If C is a choice, then it does not intercept the y axis, or x cannot be 0. This is not true, because (0, 1) is on the graph.

Finally, we have D. It intercepts the y axis (we have proven this in C). So, this is the only answer choice that is correct.

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3 years ago

under a dilation, the point (2,6) is moved to (6,18) what is the scale factor of the dilation? enter your answer in the box

Anestetic [448]

Step-by-step explanation:

The equation of line passing through the two points is $\frac{y-y_{1} }{x-x_{1} }=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

When substituted,the equation becomes $\frac{y-6}{x-2}=\frac{18-6}{6-2}$

which when simplified is $y=3\times x$

The line clearly passes through origin.

The distance between two points is $\sqrt{(y_{1}-y_{2} )^{2}+(x_{1}- x_{2} )^{2}}$

Distance between origin and $(2,6)$ is $\sqrt{40}$ .

Distance between origin and $(6,18)$ is $\sqrt{360}$

Scale factor is $\frac{distance\text{ }of\text{ }p_{2}\text{ from origin}}{distance \text{ } of \text{ } p_{1}\text{ from origin}}$

So,scale factor is $\frac{\sqrt{360} }{\sqrt{40} }$

which when simplified becomes 3.

6 0

3 years ago

Give a real life example of two variables that very directly

Snowcat [4.5K]

Answer:

the amount of products a company sells directly affects the amount of money it has

7 0

3 years ago

Given: tangent A = negative StartRoot 15 EndRoot What is the value of Tangent (A minus StartFraction pi over 4 EndFraction)?

marshall27 [118]

Answer:

( √15 + 8)/7

Step-by-step explanation:

TanA = -√15

.we are to find tan(A-π/4).

In trigonometry

Tan(A-B) = TanA - TanB/1+ tanAtanB

Hence:

tan(A-π/4) = TanA - Tanπ/4/1+ tanAtanπ/4

Substitute tan A value into the formula

tan(A-π/4) = -√15-tanπ/4 / 1+(-√15)(tanπ/4

tan(A-π/4) = -√15-1/1-√15

Rationalize

-√15-1/1-√15 × 1+√15/1+√15

= -√15-√225-1-√15/(1-√225)

= -2√15-15-1/1-15

= -2√15 -16/(-14)

= -2(√15+8)/-14

= √15 + 8/7

Hence the required value is ( √15 + 8)/7

4 0

2 years ago

Read 2 more answers

A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

<em>Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.</em>

So, Let X = No. of defective bulbs in a box

<u>Mean of X</u>, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

<u>Standard deviation of X</u>, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

5 0

3 years ago