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ololo11 [35]
3 years ago
7

Which region did the Visigoths most likely settle?

Mathematics
2 answers:
Vlada [557]3 years ago
8 0

Answer:

Gallic i believe

Step-by-step explanation:

Naddika [18.5K]3 years ago
6 0

Answer:

It was Romania, so Spain.

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Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard devia
lesya692 [45]

Answer: P(x > - 0.23) = 0.41

Step-by-step explanation:

Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = the readings at freezing on a batch of thermometers.

µ = mean temperature reading

σ = standard deviation

From the information given,

µ = 0°C

σ = 1.00°C

the probability of obtaining a reading less than -0.23°C is expressed as

P(x > - 0.23)

For x = - 0.23

z = (- 0.23 - 0)/1 = - 0.23

Looking at the normal distribution table, the probability corresponding to the z score is 0.41

7 0
3 years ago
Find the volume of the cylinder in terms of pi.
Allushta [10]

Answer:

\large\boxed{V=81\pi\ in^3}

Step-by-step explanation:

The formula of a volume of a cylinder:

V=\pi r^2H

r - radius

H - height

We have r = 3in and H = 9in. Substitue:

V=\pi(3^2)(9)=\pi(9)(9)=81\pi\ in^3

5 0
3 years ago
Prove each of the following statements below using one of the proof techniques and state the proof strategy you use.
pochemuha

Answer:

See below

Step-by-step explanation:

a) Direct proof: Let m be an odd integer and n be an even integer. Then, there exist integers k,j such that m=2k+1 and n=2j. Then mn=(2k+1)(2j)=2r, where r=j(2k+1) is an integer. Thus, mn is even.

b) Proof by counterpositive: Suppose that m is not even and n is not even. Then m is odd and n is odd, that is, m=2k+1 and n=2j+1 for some integers k,j. Thus, mn=4kj+2k+2j+1=2(kj+k+j)+1=2r+1, where r=kj+k+j is an integer. Hence mn is odd, i.e, mn is not even. We have proven the counterpositive.

c) Proof by contradiction: suppose that rp is NOT irrational, then rp=m/n for some integers m,n, n≠. Since r is a non zero rational number, r=a/b for some non-zero integers a,b. Then p=rp/r=rp(b/a)=(m/n)(b/a)=mb/na. Now n,a are non zero integers, thus na is a non zero integer. Additionally, mb is an integer. Therefore p is rational which is contradicts that p is irrational. Hence np is irrational.

d) Proof by cases: We can verify this directly with all the possible orderings for a,b,c. There are six cases:

a≥b≥c, a≥c≥b, b≥a≥c, b≥c≥a, c≥b≥a, c≥a≥b

Writing the details for each one is a bit long. I will give you an example for one case: suppose that c≥b≥a then max(a, max(b,c))=max(a,c)=c. On the other hand, max(max(a, b),c)=max(b,c)=c, hence the statement is true in this case.

e) Direct proof: write a=m/n and b=p/q, with m,q integers and n,q nonnegative integers. Then ab=mp/nq. mp is an integer, and nq is a non negative integer. Hence ab is rational.

f) Direct proof. By part c), √2/n is irrational for all natural numbers n. Furthermore, a is rational, then a+√2/n is irrational. Take n large enough in such a way that b-a>√2/n (b-a>0 so it is possible). Then a+√2/n is between a and b.

g) Direct proof: write m+n=2k and n+p=2j for some integers k,j. Add these equations to get m+2n+p=2k+2j. Then m+p=2k+2j-2n=2(k+j-n)=2s for some integer s=k+j-n. Thus m+p is even.

7 0
3 years ago
Multiple choice math question. Question #15
Greeley [361]

Answer:

that would also be car 1, because in a rotation like that its like you do a spin and come back to the same position, that is a 360 rotation.

3 0
2 years ago
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Answer ASAP pleaseeee !!!!
marshall27 [118]
Whshahjajjdbfkdbskwuw
5 0
3 years ago
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