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lukranit [14]
3 years ago
15

15. Simplify sin(90° - O) cos 0 - sin(180° +0) sin e.​

Mathematics
1 answer:
dalvyx [7]3 years ago
4 0

Answer:  cos²(θ) + sin(θ)sin(e)

<u>Step-by-step explanation:</u>

sin (90° - θ)cos(Ф) - sin(180° + θ) sin(e)

Note the following identities:

sin (90° - θ) = cos(x)

sin (180° + θ) = -sin(x)

Substitute those identities into the expression:

   cos(x)cos(x)  -  -sin(x)sin(e)

=  cos²(x) + sin(x)sin(e)

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Someone please help me!! I'll give brainliest
MariettaO [177]

Answer:

sorry to answer late but..

Step-by-step explanation:

\frac{1}{75} cm = \frac{scale }{real}

the wings of the real plane are 12 meters or 1200 cm

we want to solve for the scale, sooo do the algebra...get scale by it self..

real * \frac{1}{75} = scale

1200 * \frac{1}{75} = 16

The scale model wings are 16 cm   2.54 cm is one inch so the wings are approx.  6.3 inches

4 0
3 years ago
Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
3 years ago
Please can someone help me?
Debora [2.8K]
If the perimeters are equal, you can form an equation to find x:
x + x + 12 + x + x + 12 = x + 11 + x + 11 + x + 16
4x + 24 = 3x + 38
- 3x
x + 24 = 38
- 24
x = 14
Now you can substitute the x value into the perimeter:
(4 × 14) + 24
56 + 24 = 80 cm

(3 × 14) + 38
42 + 38 = 80 cm

So the perimeter would be 80 cm.
I hope this helps!
6 0
3 years ago
If CE bisects ZBCD and if m ZBCE = 3x - 6
horrorfan [7]

Answer:

m∠BCD = 90°

∠BCD is a right angle

Step-by-step explanation:

<em>If a ray bisects an angle, that means it divides the angle into two equal parts in measure</em>

∵ Ray CE bisects ∠BCD

→ Means divide it into two angles BCE and ECD which equal in measures

∴ m∠BCE = m∠ECD = \frac{1}{2} m∠BCD

∵ m∠BCE = 3x - 6

∵ m∠ECD = 2x + 11

→ Equate them to find x

∴ 3x - 6 = 2x + 11

→ Add 6 to both sides

∵ 3x - 6 + 6 = 2x + 11 + 6

∴ 3x = 2x + 17

→ Subtract 2x from both sides

∵ 3x - 2x = 2x - 2x + 17

∴ x = 17

∵ m∠BCE =  \frac{1}{2} m∠BCD

→ Substitute x in the measure of ∠BCE to find it, then use it to

   find m∠BCD

∵ m∠BCE = 3(17) - 6 = 51 - 6

∴  m∠BCE = 45°

∵ 45 = \frac{1}{2} m∠BCD

→ Multiply both sides by 2

∴ 90 = m∠BCD

∴ m∠BCD = 90°

→ The measure of the acute angle is less than 90°, the measure of

   the obtuse angle is greater than 90°, and the measure of the

   right angle is 90°

∴ ∠BCD is a right angle

6 0
3 years ago
Combine the like terms to create an equivalent expression: −4p+(−6p)
Step2247 [10]

Answer:

the answer is -10p

5 0
4 years ago
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