Answer:
sorry to answer late but..
Step-by-step explanation:
= 
the wings of the real plane are 12 meters or 1200 cm
we want to solve for the scale, sooo do the algebra...get scale by it self..
real *
= scale
1200 *
= 16
The scale model wings are 16 cm 2.54 cm is one inch so the wings are approx. 6.3 inches
Answer:
2 - 
Step-by-step explanation:
Using the addition formula for tangent
tan(A - B) =
and the exact values
tan45° = 1 , tan60° =
, then
tan15° = tan(60 - 45)°
tan(60 - 45)°
= 
=
Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.
The conjugate of 1 +
is 1 -
=
← expand numerator/denominator using FOIL
= 
= 
=
+ 
= 2 - 
If the perimeters are equal, you can form an equation to find x:
x + x + 12 + x + x + 12 = x + 11 + x + 11 + x + 16
4x + 24 = 3x + 38
- 3x
x + 24 = 38
- 24
x = 14
Now you can substitute the x value into the perimeter:
(4 × 14) + 24
56 + 24 = 80 cm
(3 × 14) + 38
42 + 38 = 80 cm
So the perimeter would be 80 cm.
I hope this helps!
Answer:
m∠BCD = 90°
∠BCD is a right angle
Step-by-step explanation:
<em>If a ray bisects an angle, that means it divides the angle into two equal parts in measure</em>
∵ Ray CE bisects ∠BCD
→ Means divide it into two angles BCE and ECD which equal in measures
∴ m∠BCE = m∠ECD =
m∠BCD
∵ m∠BCE = 3x - 6
∵ m∠ECD = 2x + 11
→ Equate them to find x
∴ 3x - 6 = 2x + 11
→ Add 6 to both sides
∵ 3x - 6 + 6 = 2x + 11 + 6
∴ 3x = 2x + 17
→ Subtract 2x from both sides
∵ 3x - 2x = 2x - 2x + 17
∴ x = 17
∵ m∠BCE =
m∠BCD
→ Substitute x in the measure of ∠BCE to find it, then use it to
find m∠BCD
∵ m∠BCE = 3(17) - 6 = 51 - 6
∴ m∠BCE = 45°
∵ 45 =
m∠BCD
→ Multiply both sides by 2
∴ 90 = m∠BCD
∴ m∠BCD = 90°
→ The measure of the acute angle is less than 90°, the measure of
the obtuse angle is greater than 90°, and the measure of the
right angle is 90°
∴ ∠BCD is a right angle