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Sholpan [36]
3 years ago
11

38 is what percent of 40?

Mathematics
2 answers:
guapka [62]3 years ago
4 0
38 divided by 40, then multiply by 100 = 95%
Nina [5.8K]3 years ago
4 0
38 is what percent of 40? You’d get 95 percent. If you divide 38 by 40 that’s the answer you’d get.
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F(x)= x^2– 3x + 9<br> g(x) = 3x^3+ 2x^2– 4x – 9<br> Find (f - g)(x).
denis-greek [22]

Answer:

\large \boxed{\sf \ \ -3x^3-x^2+x+18 \ \ }

Step-by-step explanation:

Hello, please consider the following.

(f-g)(x)=f(x)-g(x)=x^2-3x+9-(3x^3+2x^2-4x-9)\\\\=x^2-3x+9-3x^3-2x^2+4x+9\\\\=\boxed{-3x^3-x^2+x+18}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
CONSTRUCTION You are asked to copy a segment CD, construct a segment bisector by paper folding, and label the
lilavasa [31]

The steps on the construction of a segment bisector by paper folding, and label the midpoint M is given below.

<h3>What are the steps of this construction?</h3>

1. First, one need to open a Compass so that it is said to be more than half the length of the said segment.

2. Without altering it, with the aid of the compass, do  draw an art above and also below the said line segment from one of the segment endpoints.

3. Also without altering it and with use the compass, do draw another pair of arts from the other and points. One arc will be seen above the segment and the other or the second arc will be seen below.

4. Then do draw the point of intersection that is said to exist between the pair of arts below the line segment and also in-between the pair of arts as seen  below the line segment

5. Lastly, do make use of a straight edge to link the intersection points between the both pair of arts.

Learn more about segment bisector from

brainly.com/question/24736149

#SPJ1

5 0
2 years ago
Can anybody helppp meee please
crimeas [40]

Answer:

r^2=(A/pi)

Step-by-step explanation:

if A=pi*r^2 then maybe dividing by pi to get r^2 alone says r^2=(A/pi) or to get rid of the exponent you may square root each side so r=(sqrt(A/pi))

3 0
3 years ago
68.40 5% what is the original price
olga2289 [7]

The original price would be $72. Hope this is right, and helps you.

3 0
3 years ago
The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional
jolli1 [7]

Answer:

x=\frac{16}{\sqrt[3]{2}+1 }

Step-by-step explanation:

Q= illumination

I = intensity

Q= I/d^2

Q_total = \frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}

= \frac{I}{x^2}+\frac{2I}{(16-x)^2}

now Q' = 0

⇒I{-\frac{2}{x^3}}+\frac{4}{(16-x)^3}

x=\frac{16}{\sqrt[3]{2}+1 }

[/tex]\frac{1}{x^3} = \frac{2}{(16-x)^3}

x=\frac{16}{\sqrt[3]{2}+1 }

is the required point

5 0
3 years ago
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