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bazaltina [42]
3 years ago
13

The two congruent sides of an isosceles triangle are the ?

Mathematics
1 answer:
Masteriza [31]3 years ago
3 0

Answer:

The two leg sides

Step-by-step explanation:

The two congruent sides of an isosceles triangle are the leg sides, while the base will be  "x √2" of the measurement of the congruent sides.

Remember, the rule for isosceles triangle sides is: 1, 1, √2.

~

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Answer:2-4

Step-by-step explanation:

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(6.15x+0.24y)÷1.5+5.9x−1.6y Help plz
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Answer:

10x − 1.44y

Step-by-step explanation:

(6.15x + 0.24y) ÷ 1.5 + 5.9x − 1.6y =

= 4.1x + 0.16y + 5.9x − 1.6y

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Divide 3,479 by 9. What is the remainder?
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5/9 is the remainder
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We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. (a) Find the probability th
Verizon [17]

Answer:

a) There is a 16.6% probability that doubles were rolled.

b) Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

c) There is a 30.55% probability that at least one die is a 1.

Step-by-step explanation:

The probability formula is the number of desired outcomes divided by the number of total outcomes.

(a) Find the probability that doubles were rolled. (i.e. the two outcomes are equal)

There are six desired outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)

There are 36 total outcomes. So:

P = \frac{6}{36} = 0.166

There is a 16.6% probability that doubles were rolled.

(b) Given that the roll resulted in a sum of 6 or less, find the conditional probability that doubles were rolled.

The following rolls result in a sum of 5 or less:

(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)

So, there are 15 total outcomes.

3 of them are doubled: (1,1), (2,2), (3,3). So

P = \frac{3}{15} = 0.2

Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

(c) Find the probability that at least one die is a 1

The following outcomes have at least one die that is 1:

(1,1), (1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1)

So, there are 11 desired outcomes out of 36.

P = \frac{11}{36} = 0.3055

There is a 30.55% probability that at least one die is a 1.

6 0
4 years ago
Solve for x <br><br> 2x-20=450
Pachacha [2.7K]

2x-20=450

2x=450+20

2x/2=470/2

x=235

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3 years ago
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