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leva [86]
3 years ago
14

(6.15x+0.24y)÷1.5+5.9x−1.6y Help plz

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0

Answer:

10x − 1.44y

Step-by-step explanation:

(6.15x + 0.24y) ÷ 1.5 + 5.9x − 1.6y =

= 4.1x + 0.16y + 5.9x − 1.6y

= 10x − 1.44y

sasho [114]3 years ago
3 0

Answer:

Step-by-step explanation:

(6.15x + 0.24y)÷1.5 + 5.9x - 1.6y

=\frac{6.15}{1.5}x+\frac{0.24y}{1.5}+5.9x-1.6y\\\\=4.1x+0.16y+5.9x-1.6y\\\\=4.1x+5.9x+0.16y-1.6y\\\\=10x - 1.44y

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2) Juan had $622 in his checking account. He deposited a check for $180, and $100
adoni [48]

Answer:

867

Step-by-step explanation:

622+180+100=902

902-35=867

3 0
2 years ago
1/3x+y=4 help please?
professor190 [17]
\frac{1}{3}x+y=4\ \ \ \ \ |subtract\ \frac{1}{3}x\ from\ both\ sides\\\\y=4-\frac{1}{3}x
8 0
2 years ago
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Marie is cleaning her clothes out of the closet in her spare bedroom. She started with 650 of her items in the closet. She has b
Lemur [1.5K]

Wording is everything. Here, there are some issues. "... at the rate of 1/2 per month" can be interpreted to mean that at the end of the first month, there are 649 1/2 items in Marie's closet (decreased  by 1/2 from 650).

"The number of items Dustin adds" could mean 5 items, the number he adds each month. The wording should specify the time period or whether we're talking about the total number Dustin has added.

We assume your description means that the number of items in Marie's closet at the end of each month is 1/2 what it was at the beginning. (As opposed to decreasing by 1/2 item each month.) We assume we're interested in the total number of items of Dustin's that are in the closet.

Marie's quantity can be modeled by ...

... m = 650·(1/2)^t . . . . . t = time in months

Dustin's quantity can be modeled by ...

... d = 5t

There will be one solution for d=m, at about t = 4.8. At that point, Dustin will have added about 24 items, which will be the number Marie is down to.

There is a viable solution for d=m at about t = 4.8.

4 0
2 years ago
Read 2 more answers
Solve the equation for x ......... <br>​
Iteru [2.4K]

Answer:

-30

Step-by-step explanation:

-x/10 = 3

-x = 3 * 10 (transposing)

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x = -30

3 0
2 years ago
How are exponents and radicals used to present roots of real numbers
MissTica

Answer:

       \sqrt[n]{a}  =a^{\frac{1}{n}}

Explanation:

Roots of real numbers can be represented by <em>radicals</em> or by<em> exponents. </em>

First, I present some examples to show how exponents and radicals are related, and then generalize.

      \sqrt{4}=4^{(\frac{1}{2})}=(2^2)^\frac{1}{2}=(2)^{\frac{2}{2}}=2^1=2\\\\\\\sqrt{25}=(25)^{\frac{1}{2}}=(5^2)^{\frac{1}{2}}=(5)^{\frac{2}{2}}=5^1=5

       \sqrt[3]{8}=(8)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}=(2)^{\frac{3}{3}}=2^1=2

When you write 5² = 25, then 5 is the square root of 25.

And in general, if n is a positive integer and a^n=x , then a is the nth root of x.

Also, if n even (and positive)  and a is positive, then a^{\frac{1}{n}}   is the positive nth root of a

Thus,

       \sqrt[n]{a}  =a^{\frac{1}{n}}

5 0
2 years ago
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