Answer:
867
Step-by-step explanation:
622+180+100=902
902-35=867
Wording is everything. Here, there are some issues. "... at the rate of 1/2 per month" can be interpreted to mean that at the end of the first month, there are 649 1/2 items in Marie's closet (decreased by 1/2 from 650).
"The number of items Dustin adds" could mean 5 items, the number he adds each month. The wording should specify the time period or whether we're talking about the total number Dustin has added.
We assume your description means that the number of items in Marie's closet at the end of each month is 1/2 what it was at the beginning. (As opposed to decreasing by 1/2 item each month.) We assume we're interested in the total number of items of Dustin's that are in the closet.
Marie's quantity can be modeled by ...
... m = 650·(1/2)^t . . . . . t = time in months
Dustin's quantity can be modeled by ...
... d = 5t
There will be one solution for d=m, at about t = 4.8. At that point, Dustin will have added about 24 items, which will be the number Marie is down to.
There is a viable solution for d=m at about t = 4.8.
Answer:
-30
Step-by-step explanation:
-x/10 = 3
-x = 3 * 10 (transposing)
-x = 30
x = -30
Answer:
![\sqrt[n]{a} =a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Explanation:
Roots of real numbers can be represented by <em>radicals</em> or by<em> exponents. </em>
First, I present some examples to show how exponents and radicals are related, and then generalize.

![\sqrt[3]{8}=(8)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}=(2)^{\frac{3}{3}}=2^1=2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%3D%288%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%282%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%282%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3D2%5E1%3D2)
When you write 5² = 25, then 5 is the square root of 25.
And in general, if n is a positive integer and
, then
is the nth root of x.
Also, if n even (and positive) and
is positive, then
is the positive nth root of 
Thus,
![\sqrt[n]{a} =a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)