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3 years ago

Help please I don’t get it

Mathematics

2 answers:

AlexFokin [52]3 years ago

8 0

Answer:

3/8

Step-by-step explanation:

Rearrange, find common denominator.

$x = \frac{7}{8} - \frac{1}{2} \\ x = \frac{7}{8} - \frac{4}{8} \\ x = \frac{3}{8}$

ad-work [718]3 years ago

3 0

Answer will be 3/8 after finding the common denominators

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Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)

Orlov [11]

Answer:

Step-by-step explanation:

F (X, Y , Z)=Σm(0,1, 2 , 4 , 6) mixterms

= π M ( 3, 5, 7 ) maxterms

Please view the remaining part of the solution in the file attached below.

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3 years ago

If $500 is shared in the ratio 2:3:9 then the difference between the largest and the smallest shares is

madreJ [45]

Answer:

$250

Step-by-step explanation:

Total parts:

2+3+9 = 14

500/14 = 250/7

2×250/7 : 3×250/7 : 9×250/7

500/7 : 750/7 : 2250/7

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3 years ago

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A line that includes the point ( - 4, - 1) has a slope of - 2. What is its equation in point-slope form?

Grace [21]

Point slope form says the line through (a,b) with slope m is

y - b = m(x - a)

Here that's

y - - 1 = -2(x - -4)

Answer: y + 1 = -2(x + 4)

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3 years ago

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The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°

djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, $\angle ABN$ is 37°. We can see from the diagram that $\angle ABC$ would be $180-37=$ 143°.

Also, the new bearing is N 25°E. So, $\angle BCA$ would be 25°.

Now we can find $\angle BAC$ . As the sum of the internal angle of a triangle is 180°.

$\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12$

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is $AC=x$

We can apply the sine rule now.

$\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles$

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0

3 years ago

???????????i need help on this ASAP!!!!

ioda

Super easy all you do is grab 3500*0.7306 which equals 2557.1 2557.1 is correct hope this helps

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3 years ago

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