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Leno4ka [110]
3 years ago
7

A school cafeteria makes cheese sauce for macaroni using 15 cups of swiss cheese 17 cups of cheddar cheese. Perry tries to make

the sauce for a family party using 5 cups of swiss cheese and 7 cups of cheddar cheese. is Perry using the correct ratio? explain. (pls do explain. it's on my school work and I need an explanation.)
(middle school ratios)
Mathematics
2 answers:
vladimir2022 [97]3 years ago
6 0

Cafeteria ratio of Swiss cheese to cheddar cheese is 15:17.

Perry’s ratio of Swiss chess to cheddar cheese is 5:7.

Wrong ratio because 5 * 3 = 15 but 7 * 3 does not equal 17.

Anon25 [30]3 years ago
5 0

For this case we have that by definition, it is known as proportion to the relationship of equality that exists between two reasons, that is, between two comparisons. That is: if \frac {a} {b}is a ratio, then the equality \frac {a} {b} = \frac {c} {d} will be a proportion.

Then, 15 cups of Swiss cheese for every 17 cheddar:

15:17\\\frac {15} {17}

We want to verify the proportion:

15:17 :: 5: 7\\\frac {15} {17} = \frac {5} {7}\\7 * 15 = 5 * 17

Equality is not met!

Answer:

You are not using the correct proportion

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3. Given the graph below, determine whether each statement is true or false.
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======================================

Explanation:

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Question Help
klasskru [66]

Answer:

16 times

Step-by-step explanation:

\textsf{Volume of a cone}=\sf \dfrac{1}{3} \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

If only the radius is changed, the change in volume will be proportionate to the multiplicative factor squared.

\sf \implies Volume =\dfrac{1}{3} \pi (ar)^2h=\dfrac{1}{3} \pi (a^2)r^2h

Therefore, if the cone is quadrupled (multiplied by 4), the volume of the larger cone will be 4² times greater than the volume of the smaller cone, so <u>16 times greater </u>than the smaller cone.

<h3><u>Proof</u></h3>

Given:

  • radius = 6
  • height = 9

Substituting the given values into the formula:

\sf \implies Volume =\dfrac{1}{3} \pi (6)^2(9)=108 \pi \: \:cubic\:units

If the radius is quadrupled:

  • radius = 6 × 4 = 24
  • height = 9

Substituting the new given values into the formula:

\sf \implies Volume =\dfrac{1}{3} \pi (24)^2(9)=1728 \pi \: \:cubic\:units

To find the number of times greater the volume of the large cone is than the volume of the smaller cone, divide their volumes:

\sf \implies \dfrac{V_{large}}{V_{small}}=\dfrac{1728\pi}{108\pi}=16

So the volume of the larger cone is <u>16 times greater</u> than the volume of the smaller cone.

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2 years ago
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