We need to use the pythagorean theorem
a^2 + b^2 = c^2
where a and b are the legs, and c is the hypotenuse
47^2 + 18^2 = c^2
c = sqrt(2533)
c = 50.33
The length of the wire is 50.33 meters.
(See attached image.)
Angle QPS is an inscribed angle. Arc QS is the intercepted arc of that angle. The rule is that the intercepted arc is twice its angle measure. P measures 20 degrees, so arc QS measures 40 degrees. It just so happens that angle QTS is ALSO an inscribed angle intercepting arc QS. So angle QTS measures the same as angle P, 20 degrees. That's a. For b., we already stated the rule and figured out that minor arc QS is 40 degrees. For c., major arc QTS is 360 (the measure around the outside of a circle...EVERY circle in the world) minus the minor arc of 40. So major arc QTS measures 360 - 40 which is 320 degrees. There you go!
DE is 31 units, EF is 31 units and DF is 62 units
Step-by-step explanation:
A mid-point of a line segment
- Divides it into two congruent parts
- The length of each part is half the length of the line segment
∵ E is the mid-point of segment DF
- That means E divides DF into two parts DE and EF and the
lengths of them are equal
∴ DE ≅ EF
∵ DE = 6x + 1
∵ EF = 7x - 4
- Equate them
∴ 6x + 1 = 7x - 4
- Add 4 to both sides
∴ 6x + 5 = 7x
- Subtract 6x from both sides
∴ 5 = x
Substitute the value of x in DE and EF to find their length
∵ DE = 6(5) + 1
∵ DE = 30 + 1
∴ DE = 31 units
∵ EF = 7(5) - 4
∴ EF = 35 - 4
∴ EF = 31 units
∵ DF = DE + EF
∴ DF = 31 + 31
∴ DF = 62 units
DE is 31 units, EF is 31 units and DF is 62 units
Learn more:
You can learn more about the mid-point in brainly.com/question/10480770
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Hello,
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Thanks for the incorrect formula!
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I have tested (fog)(x) ,(f*g)(x) and finally (f+g)(x)
f(x)=6x++++++++++++++++++++++++3
g(x)=x-7
(f+g)(x)=6x+3+x-7=7x-4
(f+g)(3)=7*3-4=17
Answer B
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