Solve the System of Equations -4x + 9y = 14 12x - 10y = - 8
2 answers:
Answer:
(1, 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
Equality Properties
Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality
<u>Algebra I</u>
Solving systems of equations using substitution/elimination Step-by-step explanation:
<u>Step 1: Define Systems</u>
-4x + 9y = 14
12x - 10y = -8
<u>Step 2: Rewrite Systems</u>
-4x + 9y = 14
Multiply everything by 3: -12x + 27y = 42
<u>Step 3: Redefine Systems</u>
-12x + 27y = 42
12x - 10y = -8
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Elimination</em>
Combine 2 equations: 17y = 34 Divide 26 on both sides: y = 2
<u>Step 5: Solve for </u><em><u>x</u></em>
Define equation: 12x - 10y = -8 Substitute in <em>y</em>: 12x - 10(2) = -8 Multiply: 12x - 20 = -8 Isolate <em>x</em> term: 12x = 12 Isolate <em>x</em>: x = 1
Step-by-step explanation:
HERE,
two equation are,
●-4x+9y=14••••••••••••(equation I )
●12x-10y=-8•••••••••••(equation II )
First multiplying 3 in equation I
we get ,
= ••(equation III )
Then ,
we combine the equationi i and equation III .
we get that,
Then ,
put the value of y in equation II .
WE get,
So ,
<em>solution</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>two</em><em> </em><em>equation</em><em> </em><em>(</em><em>-4x</em><em>+</em><em>9y</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>12x-10y</em><em>=</em><em>-8</em><em>)</em> <em>is</em><em> </em><em><u>(</u></em> <em><u>1</u></em> <em><u>,</u></em> <em><u>2</u></em> <em><u>)</u></em>
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