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Vanyuwa [196]
3 years ago
14

Find d^2y/dx^2 for y=(3x^2-1)^2

Mathematics
1 answer:
shtirl [24]3 years ago
5 0
Dy/x^2
And you should put (3x^2-1)^2 instead y
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iragen [17]

Answer:

75

Step-by-step explanation:

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2 years ago
3\10 x 2\3<br><br> A.5\30<br><br><br> B.6\13<br><br><br> C.1\5<br><br><br> D.5\13
kow [346]
3/10 times 2/3 3 times 2 is 5 and 10 times 3 is 30 5/30 a
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zhannawk [14.2K]

Answer:

25+40

Step-by-step explanation:

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6 0
3 years ago
(1 2/7-3/14)/8/15trying to remember how to do this
SOVA2 [1]

We will write it as a fraction in ordet to solve, that is:

\frac{(1\frac{2}{7}-\frac{3}{14})}{(\frac{8}{15})}

We then operate as follows:

\frac{((\frac{7}{7}+\frac{2}{7})-\frac{3}{14})}{(\frac{8}{15})}\Rightarrow\frac{(\frac{9}{7}-\frac{3}{14})}{(\frac{8}{15})}\Rightarrow\frac{(\frac{15}{14})}{(\frac{8}{15})}\Rightarrow\frac{15\cdot15}{14\cdot8}\Rightarrow\frac{225}{112}

We have this, since 1 integer will be equal as a numerator divided by a denominator with equal values. Examples 1 = 2/2, 1 = 45/45, ...

8 0
1 year ago
J. J. Redick is an excellent free throw shooter and makes 90% of his free throws (i.e., he has a 90% chance of making a single f
irakobra [83]

Answer:

59.049%

Step-by-step explanation:

J. J. Redick is an excellent free throw shooter and makes 90% of his free throws

P(making one free throw) =90%

Therefore:

P($making 5 consecutive free throws)=P(making 1st) X P(making 2nd) X P(making 3rd)X P(making 4th) X P(making 5th)\\\\=90\%X90\%X90\%X90\%X90\%\\\\=0.9X0.9X0.9X0.9X0.9\\\\=0.59049\\\\=59.049\%

7 0
3 years ago
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