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3 years ago

Find d^2y/dx^2 for y=(3x^2-1)^2

Mathematics

1 answer:

shtirl [24]3 years ago

5 0

Dy/x^2
And you should put (3x^2-1)^2 instead y

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What is 3.01 the one repeating what is it as a mixed number

Doss [256]

The answer: 3 1/100

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3 years ago

What is the answer??!!!!

Sveta_85 [38]

Answer cant help you

Step-by-step explanation:

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3 years ago

What is the remainder of x^5+2x^4+9x^3-6x^2+3x+3165 divided by x-5

riadik2000 [5.3K]

Answer:

8530

Step-by-step explanation:

The remainder is 5⁵ + 2(5)⁴ + 9(5)³ - 6(5)² + 3(5) + 3165 = 8530

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2 years ago

Please help with the questions in the image

iren2701 [21]

Step-by-step explanation:

This seems to be calculus 1.

Question a

We have $-2x^3 + 5x^2 + 9$

m = slope = derivative

Find the derivative / slope of $-2x^3 + 5x^2 + 9$

We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.

$\frac{d}{dx}(-2x^3 + 5x^2 + 9)$

$-6x^2 + 10x$

$m = -6x^2 + 10x$ when x = a

Now that we have this information, we can answer question b

Question b

The tangent line for Point (1, 12)

First find the slope by using our derivative.

$m = -6x^2 + 10x$

$m = -6(1)^2 + 10(1)$

$m = -6 + 10x$

$m = 4$

Now that we have our slope, use point slope form to find our tangent line

$y - 12 = 4(x - 1)$

$y(x) = 4x + 8$

Now lets do the same for the Point (2, 13)

Find the slope at the point.

$m = -6x^2 + 10x$

$m = -6(2)^2 + 10(2)$

$m = -24 + 10$

$m = -4$

Now find the tangent line using point slope form of a line.

$y(x) - 13 = -4(x - 2)$

$y(x) = -4x + 21$

Now graph the lines, which I have done and you can see by viewing the image I have attached.

6 0

3 years ago

Astronomers measure large distances in light-years. One light-year is the distance that light can travel in one year, or approxi

Semenov [28]

Answer:

Option B - $=8.4672\times 10^{13}$

Step-by-step explanation:

Given : Astronomers measure large distances in light-years. One light-year is the distance that light can travel in one year, or approximately 5,880,000,000,000 miles.Suppose a star is 14.4 light years from earth.

To find : In scientific notation, how many miles away a star is from earth?

Solution :

One light-year is the distance that light can travel in one year is = 5,880,000,000,000 miles.

In scientific notation, $5.88\times 10^{12}$ miles.

In 14.4 lights year the distance is $=14.4\times5.88\times 10^{12}$

In 14.4 lights year the distance is $=84.672\times 10^{12}$

or $=8.4672\times 10^{13}$

Therefore, Option B is correct.

5 0

3 years ago