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factor 3x^4y^3 − 15x^2y^2 + 6xy
to Wolfram Alpha.
3xy(x^3y^2 − 5xy + 2) is the "irreducible factorization".
Here the time function is h(t) = [6 + 96t - 16t^2] feet.
The initial height of the ball is 6 feet. That's when t=0. h(0)=[6+0-0] ft = 6 ft.
At t=7 sec, h(t) = [6 + 96t - 16t^2] feet becomes
h(7 sec) = h(t) = [6 + 96(7) - 16(7)^2] feet This produces a large negative number (-106 ft), which in theory indicates that the ball has fallen to earth and burrowed 106 feet into the soil. Doesn't make sense.
Instead, let t=1 sec. Then h(1 sec) = h(t) = [6 + 96(1) - 16(1)^2] feet
=[6 + 96 -16] ft, or 86 ft.
One sec after the ball is thrown upward, it reaches a height of 86 feet. It continues to rise, slowing down, until it finally stops for an instant and then begins to fall towards earth.
Answer:
x=5
Step-by-step explanation:
I did math and ForGOt
Based on the inscribed quadrilateral conjecture: trapezoid QPRS can be inscribed in a circle because its opposite angles are supplementary.
<h3>What is the Inscribed Quadrilateral Conjecture?</h3>
The inscribed quadrilateral conjecture states that the opposite angle of any inscribed quadrilateral are supplementary to each other. That is, they have a sum of 180 degrees.
From the diagram given, the opposite angles in the trapezoid, 115 + 65 = 180 degrees.
Therefore, we can conclude that: trapezoid QPRS can be inscribed in a circle because its opposite angles are supplementary.
Learn more about the inscribed quadrilateral conjecture on:
brainly.com/question/12238046
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